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3 years ago

12

Shoe your work I need an explanation please.

2 answers:

m_a_m_a [10]3 years ago

4 0

Answer:

12.6 m^2

Step-by-step explanation:

area of sector = 90/360 × 3.14 × 4^2

= 12.56

to the nearest tenth = 12.6 m^2

Zina [86]3 years ago

4 0

$\textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} \theta =\stackrel{\textit{in degrees}}{angle}\\ r=radius\\[-0.5em] \hrulefill\\ \theta =270\\ r=4 \end{cases}\implies A=\cfrac{(270)(\stackrel{\pi }{3.14})(4)^2}{360}\implies \underset{\textit{rounded up}}{A\approx 37.7}$

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12 points! The interior angles formed by the sides of a hexagon have measures that some to 720°. What is the measure of angle F?

statuscvo [17]

Sum would be equal to 720.
so, x-60 + x-40 + 130 + 120 + 110 + x-20 = 720
3x + 240 = 720
3x = 720 - 240
x = 480/3
x = 160

Angle F = x-20 = 160 - 20 = 140

In short, Your Answer would be 140

Hope this helps!

8 0

3 years ago

A tangent line and its normal line have a point of tangency to the function f(x) at (x,y). If the slop of the normal line is m=(

alekssr [168]

Answer:

$\displaystyle \\\left(\frac{49}{900},\frac{3761}{900}\right)$ or approximately (0.544, 4.179)

Step-by-step explanation:

A function and its tangent lines intersect when their slopes are the same. Find the x-coordinate when the slope of f(x) is equal to 8/7 by taking the derivative of f(x):

$\displaystyle\\f(x)=\sqrt{x}-x+4\\f'(x)=\frac{1}{2}\cdot\frac{1}{\sqrt{x}}-1=\frac{1}{2\sqrt{x}}-1$

Set $f'(x)$ equal to 8/7 and solve for x:

$\displaystyle \\\frac{1}{2\sqrt{x}}-1=\frac{8}{7},\\x=\frac{49}{900}$

Therefore, $f(x)$ will intersect at a point of tangency with a line of slope 8/7 at x=49/900. Plug in x=49/900 into $f(x)$ to get the y-coordinate:

$\displaystyle\\y=\sqrt{x}-x+4 \vert_{x=49/900}=\frac{3761}{900}$

⇒Answer: (49/900, 3761/900) or approximately (0.544, 4.179)

5 0

3 years ago

Which of the following are examples of a geometric sequence? Select any and all that apply: may be more than one correct answer.

nevsk [136]

Answer:

( 1 , -2 , 4 , -8 , 16 , ... )

( 9 , 3 , 1 , 1/3 , 1/9 , ... )

Step-by-step explanation:

A geometric sequence has a common ratio in consecutive terms,

In sequence,

$1, \frac{1}{2}, \frac{1}{6},\frac{1}{24},\frac{1}{120}.....$

$\frac{1/2}{1}\neq \frac{1/6}{1/2}\neq \frac{1/24}{1/6}\neq \frac{1/120}{1/24}...$

i.e.

$1, \frac{1}{2}, \frac{1}{6},\frac{1}{24},\frac{1}{120}.....$ is not a Geometric sequence,

1 , -2 , 3 , -4 , 5 , ...

$\frac{-2}{1}\neq \frac{3}{-2}\neq \frac{-4}{3}\neq \frac{5}{-4}...$

i.e. 1 , -2 , 3 , -4 , 5 , ... is not a Geometric sequence,

In sequence,

1 , -2 , 4 , -8 , 16 , ...

$\frac{-2}{1}=\frac{4}{-2}= \frac{-8}{4}= \frac{16}{-8}...$

i.e. 1 , -2 , 4 , -8 , 16 , .... is a Geometric sequence,

In sequence,

0 , 1 , 0 , -1 , 0 , .....

$\frac{1}{0}\neq \frac{0}{1}\neq \frac{-1}{0}\neq \frac{0}{-1}...$

i.e. 0 , 1 , 0 , -1 , 0 , .....is not a Geometric sequence,

In sequence,

9 , 3 , 1 , 1/3 , 1/9 , ...

$\frac{3}{9}=\frac{1}{3}= \frac{1/3}{1}= \frac{1/9}{1/3}...$

i.e. 9 , 3 , 1 , 1/3 , 1/9 , ... is a Geometric sequence,

In sequence,

1 , 3 , 5 , 7 , 9 , ...

$\frac{3}{1}\neq \frac{5}{3}\neq \frac{7}{5}\neq \frac{9}{7}...$

i.e. 1 , 3 , 5 , 7 , 9 , ... is not a Geometric sequence

4 0

3 years ago

250 divided by 10 squared equals?

navik [9.2K]

250 divided by 10 squared is 2.5

4 0

3 years ago

Read 2 more answers

Please answer I need help to pass

Goryan [66]

Answer:

the answer is A

5 0

3 years ago