3 years ago

How many solutions are there to the equation

Mathematics

2 answers:

Ber [7]3 years ago

7 0

Answer:

1 Answer which is zero

Step-by-step explanation:

Attached Picture...

Naya [18.7K]3 years ago

4 0

Answer:

I think the answer is

I AM SORRY I'M NOT SURE

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Ira Lisetskai [31]

Answer: There will be no real solutions

Explanation: If the discriminant (the part under the radical in the numerator of the quadratic equation) is less than 0, there are no real solutions. If positive, there will be two real solutions. If 0, there will be one.

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3 years ago

Check all that apply.<br> x2 + 4x - 9 = 5x + 3

kakasveta [241]

Answer:

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Step-by-step explanation:

x2 + 4x - 9 = 5x + 3

x^2 + 4x - 5x - 9 - 3 = 0

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3 years ago

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lisov135 [29]

Answer:

-4

Step-by-step explanation:

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3 years ago

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tankabanditka [31]

-5+3d+6-4d

anwers is 12/-30

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3 years ago

Use the Factor Theorem to find ALL zeros of f(x) = x^3 - x^2 - 11x + 15, given that 3 is a zero. Show all work and express zeros

ELEN [110]

Answer:

Step-by-step explanation:

by synthetic division

3) 1 -1 -11 15

| 3 6 -15 (add)

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$x=\frac{-2 \pm\sqrt{2^{2} -4*1*-5} }{2*1} \\or~x=\frac{-2 \pm\sqrt{4+20} }{2} \\or~x=\frac{-2 \pm2\sqrt{6} }{2} \\or ~x=-1 \pm \sqrt{6}$

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