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joja [24]
3 years ago
5

Perform the indicated computation. (6x10^2) (2x10^5)

Mathematics
1 answer:
nevsk [136]3 years ago
3 0

Answer:

1.2 x 10^8

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

10. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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Advocard [28]

Answer:

Congruent angles and proportional side lengths

Step-by-step explanation:

4 0
3 years ago
For one of my math assignments I have to find out which solution is,
elena55 [62]

Answer:

yeah i think they are all right :)

Step-by-step explanation:

7 0
3 years ago
How do I graph this equation?
mr Goodwill [35]

since your graph starts at 0

 replace x with 0

y = 3(0) +3 = 3

so first point would be (0,3)

then just calculate other points the same way using different x values.


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5 0
3 years ago
In a school, the ratio of teachers to girls is 1:7 while that of boys to girls is 3:4, If there are 280 girls in the school, wha
Nuetrik [128]

Answer:

The total number of pupils and their teachers = 530

                                                                             

Step-by-step explanation:

No. of girls in the school = 280

The ratio boys to girls is 3:4 and that of teachers to girls is 1:7

∴ The ratio boys to girls is 3x : 4x where, 4x = 280

and The ratio of teachers to girls is x : 7x where, 7x = 280

4x = 280

\frac{280}{4\\} = x

70 = x

So, the no. of girls in the school = 4x = 4(70) = 280 and the no. of boys in the school  = 3x = 3(70) = 210

7x = 280

\frac{280}{7\\} = x

40 = x

So, the no. of girls in the school = 7x = 7(40) = 280 and the no. of teachers in the school = x = 40

∴ The total number of pupils and their teachers = 280 + 210 + 40

                                                                             = 530

3 0
3 years ago
Help Please!<br><br> Solve for d.<br> 5+d&gt;5−d<br><br> Solve for p.<br> 2p+3&gt;2(p−3)
Keith_Richards [23]
<span>Solve for d.
5+d>5−d                    Subtract 5 from both sides of this inequality:
                              
d>d                             There is no value for d that satisfies this inequality.
                                    No value can be greater than itself.




</span><span>Solve for p.
2p+3>2(p−3)          Multiply this out:    2p+3>2p-6
</span><span>                               Subtr 3 from both sides:  2p> 2p-9

           This is equivalent to 2p+9>2p.
            We could subtr. 2p from both sides:  0>-9.

            0> -9 is always true.  Thus, the given inequality has infinitely many solutions.

</span>
3 0
3 years ago
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