Help Please! Solve for d. 5+d>5−d Solve for p. 2p+3>2(p−3)

1 answer:

3 0

Solve for d.
5+d>5−d Subtract 5 from both sides of this inequality:

d>d There is no value for d that satisfies this inequality.
No value can be greater than itself.

Solve for p.
2p+3>2(p−3) Multiply this out: 2p+3>2p-6
 Subtr 3 from both sides: 2p> 2p-9

This is equivalent to 2p+9>2p.
We could subtr. 2p from both sides: 0>-9.

0> -9 is always true. Thus, the given inequality has infinitely many solutions.

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Inez earns $160 per month by babysitting. She saves 25% of her monthly salary. If her salary increases by 10%, how much will she

Olin [163]

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3 years ago

Let P(x) = 3x³-ax+b. If P(1) = P(-1) and P(2)=16, find the values of a and b

kozerog [31]

P(1) = P(-1)

P(1) = 3 - a + b
P(-1) = -3 + a + b

-> 3 - a + b = -3 + a + b
-> 3 - a + b + 3 - a - b = 0
-> 6 - 2a = 0
-> a = 3.

P(2) = 24 - 2a + b -> 24 - (2a - b) = 16 -> 2a - b = 8
-> 6 - b = 8
b = -2.

So, a = 3 and b = -2

Recheck : P(1) = 3 - 3 + (-2) = -2
P(-1) = -3 + 3 + (-2) = -2 => P(1) = P(-1) (true)

P(2) = 24 - 6 + (-2) = 16.