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Zinaida [17]
3 years ago
5

Find the slope of the line that passes through ( 10, 97) and (-11, 2).

Mathematics
1 answer:
rjkz [21]3 years ago
3 0

Answer:

95/21

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(2-97)/(-11-10)

m=-95/-21

m=95/21

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Fill in the blank to complete the following sentence. The two roots a +sqrt b and a- sqrt b are called ______ radicals.
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The two roots a + sqrt b and a - sqrt b are called conjugate radicals.

<u>Solution:</u>

Given that the two roots a + sqrt b and a - sqrt b are called ______ radicals.

Now let us write the each of the given two radicals in mathematical form.

So, first radical ⇒ a + sqrt b ⇒ a+\sqrt{b}   [ since sqrt means square root]

Now second radical ⇒ a - sqrt b ⇒ a-\sqrt{b}

We have to find the relation between a+\sqrt{b} \text { and } a-\sqrt{b}

Now, if observe a+\sqrt{b}  is conjugate of a-\sqrt{b} \text { as }(a+\sqrt{b})(a-\sqrt{b})=a^{2}-b

[ where radical is eliminated]

Hence, the two roots a +sqrt b and a- sqrt b are called conjugate radicals

4 0
3 years ago
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mojhsa [17]
Are there any choices?

5 0
3 years ago
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ivann1987 [24]

Answer:

it ether b or c

Step-by-step explanation:

8 0
4 years ago
What is the area?<br> write your answer as a fraction or as a whole or mixed number
Soloha48 [4]

\underline \mathcal \pink{ GIVEN}

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  • Height = 4 6/7 km

\underline \mathcal \purple{ TO  \: FIND}

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\underline \mathcal \blue{CALCULATION}

\qquad \tt \leadsto \: area =  \frac{1}{2}  \times base \times height

\qquad \bf \nrightarrow \: area =  \frac{1}{ \cancel2}  \times  \cancel2 \frac{9}{10}  \times 4 \frac{6}{7}

\qquad \bf \nrightarrow \: area =   \frac{9}{ \cancel{10}}  \times  \cancel4 \frac{6}{7}

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7 0
2 years ago
LOOK AT CHART BEFORE THE BULLET PART:
tresset_1 [31]

Answer:

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Step-by-step explanation:

It can be easiest simply to solve the equation for y.

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  4y = -3x + 1596 . . . . subtract 3x

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From this equation in slope-intercept form you can read the slope as -3/4 and the y-intercept as 399. You already know the equation.

8 0
3 years ago
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