A weight of 12. 0 n hangs motionless from a spring, with a spring constant of 10. 0 n/m. How far is the spring stretched from it
1 answer:
The extension of this spring from its original length is equal to 1.2 meter.
<u>Given the following data:</u>
- Weight = 12 Newton
- Spring constant = 10 N/m
To calculate the extension of this spring from its original length:
<h3>How to solve for extension.</h3>Mathematically, the force acting on a spring is given by the formula:
<u>Where:</u>
- K is the spring constant.
- e is the extension.
Making e the subject of formula, we have:
Substituting the given parameters into the formula, we have;
Extension, e = 1.2 meter.
Read more on spring constant here: brainly.com/question/14372859
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The dvd player’s price was reduced by $3. 82 more than the stereo tuner’s price.
- Let the cost price of dvd players be D.
- Let the cost price of stereo tuners be S.
<u>Given the following data:</u>
- Markdown for dvd player = 36%
- Markdown for stereo tuner = 22%
- Markdown cost for dvd player = $41.60
- Markdown cost for stereo tuner = $69.42
To determine which item’s price was reduced by more, and by how many dollars:
First of all, we would calculate the cost price of each item.
<u>For </u><u>dvd players</u><u>:</u>
<u>Note:</u> You'll pay 64% since it was markdown by 36%.
D = $65
Reduction: Dvd player = $23.40
<u>For </u><u>stereo tuners</u><u>:</u>
<u>Note:</u> You'll pay 78% since it was markdown by 22%.
D = $89
Reduction: Stereo tuner = $19.58
Now, we can calculate the difference in reduction of the cost price of both items:
Difference = $3.82
Therefore, the price of the dvd players was reduced by $3. 82 more than the price of the stereo tuners.
Read more on markdown here: brainly.com/question/11676563