A weight of 12. 0 n hangs motionless from a spring, with a spring constant of 10. 0 n/m. How far is the spring stretched from it
1 answer:
The extension of this spring from its original length is equal to 1.2 meter.
<u>Given the following data:</u>
- Weight = 12 Newton
- Spring constant = 10 N/m
To calculate the extension of this spring from its original length:
<h3>How to solve for extension.</h3>Mathematically, the force acting on a spring is given by the formula:
<u>Where:</u>
- K is the spring constant.
- e is the extension.
Making e the subject of formula, we have:
Substituting the given parameters into the formula, we have;
Extension, e = 1.2 meter.
Read more on spring constant here: brainly.com/question/14372859
You might be interested in
In this exercise we have to use the properties of the logarithm to write it in one way, like this:
From these recalling some properties of the logarithm, we find that:
- When the logarithm is equal to the base, the logarithm will always be equal to 1.
- Logarithm of any base, whose logarithm is equal to 1, will always have the result equal to 0.
- Two logarithms with the same base are equal when the logarithms are also equal.
given the equation as:
See more about logarithm at brainly.com/question/10486788