Question

A weight of 12. 0 n hangs motionless from a spring, with a spring constant of 10. 0 n/m. How far is the spring stretched from its original length? 0. 120 m 0. 220 m 0. 833 m 1. 20 m.

Answer 1

The extension of this spring from its original length is equal to 1.2 meter.

Given the following data:

• Weight = 12 Newton

• Spring constant = 10 N/m

To calculate the extension of this spring from its original length:

How to solve for extension.

Mathematically, the force acting on a spring is given by the formula:

$F=ke$

Where:

• K is the spring constant.

• e is the extension.

Making e the subject of formula, we have:

$e=\frac{F}{k}$

Substituting the given parameters into the formula, we have;

$e=\frac{12}{10}$

Extension, e = 1.2 meter.

Read more on spring constant here: brainly.com/question/14372859