Then move all terms not containing x from the center section of the inequality.
-2<x<3
Firstly, the rate of increase of Canton = 80/7720 = 0.010
The rate of increase of HP = 120/3200 = 0.0375
Apply the formula of compound interest==> A =A'(1+i)^n
The population will be equal when the following equality is satisfied
7720(1+0.01)^n = 3200(1+0.0375)^n
or
7720x1.01^n = 3200x1.0375^n
Divide both sides by 3200 ===>(193/80)x1.01^n=1.0375^n
Answer:
The expected monetary value of a single roll is $1.17.
Step-by-step explanation:
The sample space of rolling a die is:
S = {1, 2, 3, 4, 5 and 6}
The probability of rolling any of the six numbers is same, i.e.
P (1) = P (2) = P (3) = P (4) = P (5) = P (6) = 
The expected pay for rolling the numbers are as follows:
E (X = 1) = $3
E (X = 2) = $0
E (X = 3) = $0
E (X = 4) = $0
E (X = 5) = $0
E (X = 6) = $4
The expected value of an experiment is:

Compute the expected monetary value of a single roll as follows:
![E(X)=\sum x\cdot P(X=x)\\=[E(X=1)\times \frac{1}{6}]+[E(X=2)\times \frac{1}{6}]+[E(X=3)\times \frac{1}{6}]\\+[E(X=4)\times \frac{1}{6}]+[E(X=5)\times \frac{1}{6}]+[E(X=6)\times \frac{1}{6}]\\=[3\times \frac{1}{6}]+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]\\+[0\times \frac{1}{6}]+[0\times \frac{1}{6}]+[4\times \frac{1}{6}]\\=1.17](https://tex.z-dn.net/?f=E%28X%29%3D%5Csum%20x%5Ccdot%20P%28X%3Dx%29%5C%5C%3D%5BE%28X%3D1%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D2%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D3%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%2B%5BE%28X%3D4%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D5%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5BE%28X%3D6%29%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%3D%5B3%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B0%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%2B%5B4%5Ctimes%20%5Cfrac%7B1%7D%7B6%7D%5D%5C%5C%3D1.17)
Thus, the expected monetary value of a single roll is $1.17.