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3 years ago

a school auditorium has 4 sections.Each seat takes up1/25 of a section.how many seats are in the auditorium?

Mathematics

2 answers:

Whitepunk [10]3 years ago

8 0

100 seats total.
there are 25 seats per section and 4 sections
they just add in fancy stuff to make it confusing.

Kisachek [45]3 years ago

7 0

The answer is 100 seats

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Deon does a weekly exercise program consisting of cardiovascular work and weight training. Each week, he exercises for at least

LenKa [72]

Answer:

see attached

Step-by-step explanation:

The line at the lower left of the shaded region is x+y=12. The shaded area is above that line because is represents a minimum amount of exercise.

7 0

3 years ago

A tank contains 240 liters of fluid in which 20 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu

Novosadov [1.4K]

Answer:

$A(t)=240-220e^{-\frac{t}{40}}$

Step-by-step explanation:

A tank contains 240 liters of fluid in which 20 grams of salt is dissolved.

Volume of the tank = 240 liters
Initial Amount of Salt in the tank, A(0)=20 grams

Brine containing 1 gram of salt per liter is then pumped into the tank at a rate of 6 L/min

$R_{in}=$ (concentration of salt in inflow)(input rate of fluid)

$R_{in}=(1\frac{gram}{liter})( 6\frac{Liter}{min})=6\frac{gram}{min}$

$R_{out}=$ (concentration of salt in outflow)(output rate of fluid)

$R_{out}=(\frac{A(t)}{240})( 6\frac{Liter}{min})\\R_{out}=\frac{A}{40}$

Rate of change of the amount of salt in the tank:

$\dfrac{dA}{dt}=R_{in}-R_{out}$

$\dfrac{dA}{dt}=6-\dfrac{A}{40}$

We then solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{40}=6\\$The integrating factor: e^{\int \frac{1}{40}dt} =e^{\frac{t}{40}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{40}}+\dfrac{A}{40}e^{\frac{t}{40}}=6e^{\frac{t}{40}}\\(Ae^{\frac{t}{40}})'=6e^{\frac{t}{40}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{40}})'=\int 6e^{\frac{t}{40}} dt\\Ae^{\frac{t}{40}}=6*40e^{\frac{t}{40}}+C, $(C a constant of integration)\\Ae^{\frac{t}{40}}=240e^{\frac{t}{40}}+C\\$Divide all through by e^{\frac{t}{40}}\\A(t)=240+Ce^{-\frac{t}{40}}$

Recall that when t=0, A(t)=20 (our initial condition)

$20=240+Ce^{-\frac{0}{40}}\\20-240=C\\C=-220\\$Therefore, the number A(t) of grams of salt in the tank at time t\\A(t)=240-220e^{-\frac{t}{40}}$

3 0

3 years ago

luke earned $54 after mowing 3 lawns. write an equation comparing earnings to lawns mowed .how much would luke earn after mowing

MariettaO [177]

Luke earned $54 for 3 lawns
So each lawn = $54/3 = $18

After mowing 7 lawns =
7 X $18 = $126

8 0

2 years ago

Read 2 more answers

4 times what equals 204? Explanation please.

omeli [17]

To find the answer to your question you just have to divide 204 by 4:

204 / 4 = 51

It means that 4 times 51 equals 204:

4 * 51 = 204

I hope it will help you :)

5 0

2 years ago

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40 POINTS

kaheart [24]

Answer:

He can make a maximum of $480.

Step-by-step explanation: Technically he can win all 60 times so the maximum is 60*8 = 480

8 0

3 years ago