Answer:
b=4.9
C. is the correct option.
Step-by-step explanation:
In triangle TGN,
Let <RTG be x
cosx= b/h
or, cosx = 2/a
Again,
In triangle TRG,
cosx = b/h
(for bigger right angled triangle)
cosx = a/(4+2)
cosx = a/6
Now
cosx = 2/a = a/6
or, 2/a = a/6
or, 12 = a²
so, a² = 12
Now,
For TRG,
h² = p²+b²
or, 6² = b² + a²(a²=12)
or, 6² = b² + 12
or, 36 = b² + 12
or, 36 -12 = b²
or, b² = 24
or, b = square root 24
so, b = 4.8989
so, b = 4.9
Answer:
74
Step-by-step explanation:
you first simplify 2/1 and then 78- (2*2)
You just need to make them all the same common denominator. do you still need help?
Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
