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andrey2020 [161]
2 years ago
9

HELP NO LINKS PLS PLS

Mathematics
1 answer:
7nadin3 [17]2 years ago
4 0

Answer:

its 13.42 yards you multipy by 6.1 and 2.2

Step-by-step explanation:

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What is the difference between an approximate and an exact number?
Aleks [24]

Answer:

An approximate number is a close number that is only off by x number of places (Like a rounded number). An exact number is exactly correct. For example:

3 - 1.5 is approximately 2, but is exactly 1.5.

Mark Brainliest if this helps!

7 0
3 years ago
A rectangle has a perimeter of 32 in. find the length and width of the rectangle under which the area is the largest. follow the
Dafna1 [17]
Let width and length be x and y respectively.
Perimeter (32in) =2x+2y=> 16=x+y => y=16-x
Area, A = xy = x(16-x) = 16x-x^2
The function to maximize is area: A=16 x-x^2
For maximum area, the first derivative of A =0 => A'=16-2x =0
Solving for x: 16-2x=0 =>2x=16 => x=8 in
And therefore, y=16-8 = 8 in
5 0
3 years ago
If f(x) = 5x - 7, what is {3)?<br> O A. 22<br> O B. 2<br> O c. 1<br> • D. 8
DerKrebs [107]
<h3>Answer:  8</h3>

Work Shown:

f(x) = 5x - 7

f(3) = 5(3) - 7 .... every x replaced with 3

f(3) = 15 - 7

f(3) = 8

6 0
2 years ago
Read 2 more answers
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kotegsom [21]
It is twice the area of a square of side lengths 3 units
3 0
3 years ago
fire work a travels at the speed 300 ft/s firework b travels 240 ft/s. firework b is launched 0.25s before firework a. how many
storchak [24]

Answer:

Both fireworks  will explode after 1 seconds after firework b launches.

Step-by-step explanation:

Given:

Speed of fire work A= 300 ft/s

Speed of Firework B=240 ft/s

Time before which fire work b is launched =0.25s

To Find:

How many seconds after firework b launches will both fireworks explode=?

Solution:

Let t be the time(seconds) after which both the fireworks explode.

By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation

Firework A= 330(t)

Firework B=240(t)+240(0.25)

Since we need to know the same time after which they explode, we can equate both the equations

330(t) = 240(t)+240(0.25)

300(t)= 240(t)+60

300(t)-240(t)= 60

60(t)=60

t=\frac{60}{60}

t=1

7 0
3 years ago
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