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exis [7]
2 years ago
15

What is the coefficient of the 3rd term of : 2x^3 + 3x^2 - 5x + 14

Mathematics
1 answer:
LenaWriter [7]2 years ago
5 0

Answe

Step-by-step explanation

:dominio x∈

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Use the substitution method to sloved the systmem of equaions. Choose the correct order pair
vazorg [7]
X= 12 + y
So then plug in
12 + y + y = 12
2y=0
Y= 0
X + 0 = 12
X= 12
this is prob wrong lol but hopefully it helps
4 0
2 years ago
Find the value of “x” so that a parallel to b
Kaylis [27]

Answer:

Step-by-step explanation:

3x - 50 = 2x - 5     { a// b,  so alternate interior angles are equal}

3x - 2x = -5 +50

        x = 45

8 0
3 years ago
Read 2 more answers
Donna wants to decorate her bulletin board she has 38 meters of green ribbon to go around the bulletin board and she has to use
andreev551 [17]

If you are asking for the perimeter of the bulletin board the answer below will be correct!

Answer:

Square option: 9.5 Meters

Rectangle option: see explanation below

Step-by-step explanation:

To find the perimeter you must add the lengths of all the sides. Assuming the bulletin board is a SQUARE all four sides are going to be equal. Therefore you can divide 38 by 4 to get the length of one side (aka 9.5 meters).

Assuming the bulletin board is a RECTANGLE changes things up. You can pretty much pick any combination of numbers that will add up to 19 (because if it is a rectangle there are two pairs of equal side lengths). You could do 1 + 18, 5+14, 8+11. The options are really endless

4 0
2 years ago
Assume that college students have IQ scores that are normally distributed with a mean of 100 and a standard deviation of 15. Fin
jolli1 [7]

Answer:

0.018 is  the probability that a randomly selected college student has an IQ greater than 131.5                                

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.

Formula:

a) P(IQ greater than 131.5)

P(x > 131.5)

Calculation the value from standard normal z table, we have,  

0.018 is  the probability that a randomly selected adult has an IQ greater than 131.5

3 0
3 years ago
Find the derivative of <br> |x|/(x-1)
ki77a [65]
\bf \cfrac{|x|}{x-1}\iff \cfrac{\sqrt{x^2}}{x-1}\iff \cfrac{(x^2)^{\frac{1}{2}}}{x-1}&#10;\\\\\\&#10;\textit{using the quotient rule}&#10;\\\\\\&#10;\cfrac{dy}{dx}=\cfrac{\frac{1}{2}(x^2)^{-\frac{1}{2}}\cdot 2x(x-1)-(x^2)^{\frac{1}{2}}\cdot 1}{(x-1)^2}

\bf \cfrac{dy}{dx}=\cfrac{\frac{x(x-1)-(x^2)^{\frac{1}{2}}}{(x^2)^{\frac{1}{2}}}}{(x-1)^2}\implies \cfrac{dy}{dx}=\cfrac{x(x-1)-(x^2)^{\frac{1}{2}}}{(x^2)^{\frac{1}{2}}(x-1)^2}&#10;\\\\\\\cfrac{dy}{dx}=\cfrac{x(x-1)-|x|}{|x|(x-1)^2}
4 0
3 years ago
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