2x^2+4x-3-3X^2=0
simplify 2x^2+4x-3-3x^2 to -x^2+4x-3
-x^2+4x-3=0
Multiply both sides by -1
x^2-4x+3=0
Factor x^2-4x+3
1. Ask: Which two number add up to -4 and multiply to 3.
2. Answer:3 and -1.
3. Rewrite the expression as (x-3)(x-1):
(x-3)(x-1)=0
5Solve for x
1.Ask: when will (x-3)(x-1) equal zero.
2.Answer: when x-3=0 or x-1=0.
x=3,1
Answer:
300
Step-by-step explanation:
2.6*10 4
two. six times ten to the fourth
Answer:
θ∈{
}
Explanation:
The given equation is


Applying values on 'n' we obtain values of θ that beling to [0,2π)
For n=0, θ=
For n=1, θ =
For n=2,θ =
For n=3,θ =
Answer:
the anwer is B ( i mean second option)
And you can try it
you will find ;

HAVE A NİCE DAY
Step-by-step explanation:
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