Question

Simplify (3t^2+2t−2)+(t^2+3t−4)−(4t−5)

Answer 1

Assignment: $\bold{Simplify \ Equation: \ \left(3t^2+2t-2\right)+\left(t^2+3t-4\right)-\left(4t-5\right)}$

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Answer: $\boxed{\bold{4t^2+t-1}}$

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Explanation: $\downarrow\downarrow\downarrow$

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[ Step One ] Remove Parenthesis: (a) = a

$\bold{3t^2+2t-2+t^2+3t-4-\left(4t-5\right)}$

[ Step Two ] Simplify $\bold{-\left(4t-5\right)}$

$\bold{-4t+5}$

[ Step Three ] Rewrite Equation

$\bold{3t^2+2t-2+t^2+3t-4-4t+5}$

[ Step Four ] Simplify $\bold{3t^2+2t-2+t^2+3t-4-4t+5}$

$\bold{4t^2+t-1}$

[ Step Five ] Rewrite Equation

$\bold{4t^2+t-1}$

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$\bold{\rightarrow Mordancy \leftarrow}$

Answer 2

Answer:

 4t^2 + t  - 1.

Step-by-step explanation:

(3t^2 + 2t −2 )+(t^2 + 3t − 4) − (4t − 5)

= 3t^2 + 2t −2 + t^2 + 3t − 4 - 4t + 5

=  4t^2 + t  - 1.