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3 years ago

Solve

frac{-4x^2y^2z^4}{16x^{10}yz^3}" alt="\frac{-4x^2y^2z^4}{16x^{10}yz^3}" align="absmiddle" class="latex-formula">

Mathematics

2 answers:

HACTEHA [7]3 years ago

5 0

The answer to ur equation is -y/4x^8z

Lerok [7]3 years ago

5 0

-y/4x^8 that is the answer

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A mechanical system is governed by the following differential equation what is the homogeneous solution

Anika [276]

The ODE has characteristic equation

$r^2+6r+9=(r+3)^2=0$

with roots $r=-3$ , and hence the characteristic solution

$y_c=C_1e^{-3t}+C_2te^{-3t}$

For the particular solution, assume an ansatz of $y_p=ae^{-t}$ , with derivatives

$\dfrac{\mathrm dy_p}{\mathrm dt}=-ae^{-t}$

$\dfrac{\mathrm d^2y_p}{\mathrm dt^2}=ae^{-t}$

Substituting these into the ODE gives

$ae^{-t}-6ae^{-t}+9ae^{-t}=4ae^{-t}=4e^{-t}\implies a=1$

so that the particular solution is

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3 years ago

Write an equation of the line below.

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Answer:

y = -4x - 4

Step-by-step explanation:

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-8/2 = -4

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3 years ago

1. The slope is -2/3 and the y-intercept is 4. What is the equation of the line in Ax + By + C = 0 form?

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4 years ago

Sal is tiling his entryway. The floorplan is drawn on a unit grid. Each unit length represents 1 foot tile cost $1.25 per square

Tresset [83]

Answer: Sal will pay $77.78 to tile his entryway

Step-by-step explanation:

The image of the question is attached below.

Given each unit length = 1 foot

Tile cost per square feet = $1. 65

To find the area, split the floor shape into two shape.

One is trapezoid and the other is parallelogram.

Let's count the grid given.

The parallels sides of trapezoid are 7 ft and 4 ft, height is 7 ft.

The base and height of the parallelogram are 4 ft and 4 ft respectively.

Area of the trapezoid

Area of the trapezoid = 27.5 sq.ft

Area of the parallelogram = base × height

= 4 ft × 4 ft

Area of the parallelogram = 16 sq. ft

Total area = 27.5 sq. ft + 16 sq. ft

= 43.5 sq. ft

Cost of area per sq. ft = $1.65

Cost of area 43.5 sq. ft = 43. 5 × 1.65

= $71.775

= $71.78

Hence Sal will pay $71.78 to tile his entryway.

4 0

3 years ago

During a recent drought, a water utility in a certain town sampled 100 residential water bills and found that 80 of the residenc

Anastasy [175]

Answer: 0.893

Step-by-step explanation:

Given : Sample size of residential water bills: n=100

Number of residences had reduced their water consumption over that of the previous year = 80

Then sample proportion: $\hat{p}=\dfrac{80}{100}=0.8$

Critical value for 98% confidence= $z_{\alpha/2}=2.326$

The upper bound for confidence interval for population proportion :

$\hat{p}+ z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

$=0.8+ (2.326)\sqrt{\dfrac{0.8(1-0.8)}{100}}\\\\=0.8+0.09304=0.89304\approx0.893$

Hence, the 98% upper confidence bound for the proportion of residences that reduced their water consumption.=0.893

4 0

3 years ago