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2 years ago

Subtract mc011-1. Jpg from mc011-2. Jpg. Mc011-3. Jpg mc011-4. Jpg mc011-5. Jpg mc011-6. Jpg.

SAT

2 answers:

vesna_86 [32]2 years ago

5 0

Answer:

Explanation:

good luck

gtnhenbr [62]2 years ago

4 0

Answer:

The answer is B I just took the test!

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A train traveled 936 miles hours how far does it travel in 1 hour?

marishachu [46]

Answer:

The answer is 3 hour becasue u muiplying the 12 and 936 and getting 3 hour

Explanation:

6 0

3 years ago

Which statement will accurately correct the two-column proof? the measure of angle zry equals 180° by definition of supplementar

ankoles [38]

There are different kinds of angles. The statement that will accurately correct the two-column proof is that the definition of angle on a straight line.

<h3>What is straight angle? </h3>

This is an angle whose sides sit in opposite directions from the vertex usually in the same straight line and is said to be equals two right angles.

Two angles are known to be supplementary when their measures if sum up reaches 180 degrees.

Conclusively, Looking at the angle, m∠ZRY = 180°, this is because angle ZRY is a straight angle and it is not a supplementary angle.

Therefore option A is the correct answer (Image attached)

Learn more about Angles from

brainly.com/question/14726749

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2 years ago

Which value must be added to the expression x2 12x to make it a perfect-square trinomial?

valentinak56 [21]

Answer:

"The correct answer is 36.

A perfect square trinomial can be factored into this form: (x+a)^2Note that (x+a)^2 = x^2 + (2a)x + a^2To find the missing number, we should take the 12 (in the 12x term) and divide it by two to get 6. This number squared will be the missing number at the end of the trinomial.

Let's check that this is the correct answer.(x+6)^2 = x^2 + 12x + 36Indeed, 36 is the correct answer."

Explanation:

3 0

2 years ago

Read 2 more answers

What is the most important thing that you need to consider in writing an essay?

ipn [44]

Answer:

It depends. (check explanation)

Explanation:

To be honest, it depends on the essay you're writing. If it's a persuasive essay, then you need to focus on making your points solid and undebatable. If it's a research essay, you need to focus on citing a lot of sources. However, one thing needs to be in common in all your essays that teachers look for. Evidence. Evidence is key to developing your essay and making strong points. Most teachers look for evidence in your paragraphs and they will make your writing much more professional and give you a base to build your ideas off of. I hope this helped, please let me know if you have any further questions. :))

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3 years ago

A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin

Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

131.6 N/C

12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

$\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}$

Which gives;

$\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C$

$\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C$

Which gives;

$\vec{E}_1 = \mathbf{21.6 \, N/C \cdot \hat x + 28.8 \, N/C \hat y}$

$\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C$