Complete Question:
The mean life of a large shipment of CFLs is equal to 7,500 hours. The population standard deviation is 1,000 hours. A random sample of 64 CFLs indicate a sample life of 7,250 hours.
1. State the Null and Alternative Hypothesis.
2. At the 0.05 level of significance, is there evidence that mean life is different from 7,500 hours.
3. Construct a 95% confidence interval estimate of the population mean life of the CFLs.
4. Compute the p-value and interpret its meaning.
Answer:
-2, (7005, 7450), 0.045
Explanation:
1).
H₀: mean of life shipment is 7500 hours
the hypothesis are outlined as follows
H₀:
7500
H₁:
7500
where, n = 64, x = 7250,
1000 hours
Test statistics:

Our conclusion from the above result is that there is sufficient evidence to say that the mean life is different from 7500 hours
2). 95% confidence Interval for the population mean
is
![[7250-1.96\times \frac{1000}{\sqrt{64}},7250+1.96\times \frac{1000}{\sqrt{64}} ]\\\\(7005,7495)](https://tex.z-dn.net/?f=%5B7250-1.96%5Ctimes%20%5Cfrac%7B1000%7D%7B%5Csqrt%7B64%7D%7D%2C7250%2B1.96%5Ctimes%20%5Cfrac%7B1000%7D%7B%5Csqrt%7B64%7D%7D%20%5D%5C%5C%5C%5C%287005%2C7495%29)
3).
the p-value is given by

Based on <u>the </u><u>norm</u><u> of </u><u>reciprocity</u>, you will feel obligated to do a favor for a coworker when he or she performs a large favor for you.
<h3>What is the norm of reciprocity?</h3>
The norm of reciprocity can be defined as a social convention requires that a person repay in kind a favor or assistance that was done to them, especially to the performer of such act.
Based on <u>the </u><u>norm</u><u> of </u><u>reciprocity</u>, we can infer and logically deduce that you will feel obligated to do a favor for a coworker when he or she performs a large favor for you.
Read more on norm of reciprocity here: brainly.com/question/6860006
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Answer:
The United States has a trade deficit with China
Explanation:
Edg2020
Answer:
how long of an paper are you looking for?
Explanation:
leghth size or paragraph sized