Ask question

Ask question

All categories

2 years ago

6

Dylan is knitting a scarf, and he wants the final product to be 4 inches wide and 63 inches long. Each skein of yarn will knit a

rectangle that is 4 inches by 9 inches. How many skeins should Dylan buy?

1 answer:

vodomira [7]2 years ago

8 0

Answer:

7

Step-by-step explanation:

63 / 9 = 7

You might be interested in

the soccer team is planning to sell health bars for a fundraiser. the prices of purchasing health bars from two different compan

zubka84 [21]

40 bars __________________

4 0

4 years ago

Read 2 more answers

Approximately 64% of films are rated R. If 700 films were recently rated, how many were rated R?

soldier1979 [14.2K]

448 films were rated R

3 0

3 years ago

Please could you find the answers to the questions in the attachment.

Fudgin [204]

( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ )we need 3 equations
1. midpoint equation which is ( $\frac{x1+x2}{2} , \frac{y1+y2}{2}$ ) when you have 2 points

2. distance formula which is D= $\sqrt{(x2-x1)^{2}+(y2-y1)^{2}}$

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height

so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=( $\frac{11+19}{2} , \frac{10+6}{2}$ )
midpoint=( $\frac{30}{2} , \frac{16}{2}$ )
midpoint= (15,8)

point x=(15,8)

y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=( $\frac{5+21}{2} , \frac{8+0}{2}$ )
midpoint=( $\frac{26}{2} , \frac{8}{2}$ )
midpoint=(13,4)

Y=(13,4)

legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= $\sqrt{(19-11)^{2}+(6-10)^{2}}$
D= $\sqrt{(8)^{2}+(-4)^{2}}$
D= $\sqrt{64+16}$
D= $\sqrt{80}$
D= $4 \sqrt{5}$
BC= $4 \sqrt{5}$

X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= $\sqrt{(13-15)^{2}+(4-8)^{2}}$
D= $\sqrt{(-2)^{2}+(-4)^{2}}$
D= $\sqrt{4+16}$
D= $\sqrt{20}$
D= $2 \sqrt{5}$
XY= $2 \sqrt{5}$

the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC= $4 \sqrt{5}$ and XY= $2 \sqrt{5}$

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= $\sqrt{(21-5)^{2}+(0-8)^{2}}$
D= $\sqrt{(16)^{2}+(-8)^{2}}$
D= $\sqrt{256+64}$
D= $\sqrt{320}$
D= $4 \sqrt{2}$
AD= $4 \sqrt{2}$

so we have
AD= $4 \sqrt{2}$
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
( $4 \sqrt{2}+4 \sqrt{5}$ ) times 1/2 times $2 \sqrt{5}$ =
( $4 \sqrt{2}+4 \sqrt{5}$ ) times \sqrt{5} [/tex] =
$4 \sqrt{10}+4*5$ = $4 \sqrt{10}+20$ =80 $\sqrt{10}$ =252.982

X=(15,8)
Y=(13,4)
BC= $4 \sqrt{5}$
XY= $2 \sqrt{5}$
Area=80 $\sqrt{10}$ square unit or 252.982 square units

7 0

3 years ago

VERY EASY QUESTION. Write out this equation: ten times the sum of half a number and 6 is 8

bija089 [108]

Answer:

x

=

58

5

Step-by-step explanation:

10 times:

→

10

×

The sum of:

→

10

×

(

?

+

?

)

half a number:

→

10

×

(

x

2

+

?

)

and 6:

→

10

×

(

x

2

+

6

)

is 8 :

→

10

×

(

x

2

+

6

)

=

8

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

10

(

x

2

+

6

)

=

8

Multiply out the bracket

5

x

+

60

=

8

Subtract 60 from both sides

5

x

=

58

Divide both sides by 5

x

=

58

5

6 0

3 years ago

Read 2 more answers

Write and equation for the line that has a slope of one half and passes through the point 2,4

jekas [21]

The equation in slope intercept form is

Y=.5x+3

8 0

3 years ago