Write the linear equation in slope-intercept form and simplify. -6x – 14y = -8
1 answer:
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Answer:
Step-by-step explanation:
<em><u>Given</u></em><u>:</u> A line m is perpendicular to the angle bisector of ∠A. We call this
intersecting point as D. Hence, in figure ∠ADM=∠ADN =90°.
AD is angle bisector of ∠A. Hence, ∠MAD=∠NAD.
<u><em>To Prove</em></u>: <em><u>ΔAMN is an isosceles triangle. i.e any two sides in ΔAMN are</u></em>
<em> </em><em><u>equal. </u></em>
<em><u>Solution</u></em>: Now, In ΔADM and ΔADN
∠MAD=∠NAD ...(1) (∵Given)
AD=AD ...(2) (∵common side)
∠ADM=∠ADN ...(3) (∵Given)
<u><em> Hence, from equation (1),(2),(3) ΔADM ≅ ΔADN</em></u>
( ∵ ASA congruence rule)
⇒<u><em> AM=AN</em></u>
Now, In Δ AMN
AM=AN (∵ Proved)
Hence, ΔAMN is an isosceles triangle.
<u>Answer:</u>
The average daily balance for the month of June is 55.16
Solution:
Given, June 1st = 1223 starting balance
June 10th = 615 deposit
So these will add in the account
June 15th = withdrawal of -63
June 22nd = withdrawal of -120
These will be subtracted from the account.
We have to add the deposits and subtract the withdrawals from the starting balance to obtain the total amount.
So, the total amount deposited in June is (1223 +615-63-120) = 1655
The total days in June is 30. In 30 days, the total deposit is 1655. To calculate the average balance, we have to divide the total amount by the total number of days in the month.
So, in 1 day the deposit is
Hence, the average daily balance for June is = 55.16