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elixir [45]
2 years ago
10

Pls helpppppppppp meeeeeeeeeeeeeeee

Mathematics
1 answer:
yarga [219]2 years ago
7 0

Answer:

B. \frac{1}{5}

Hope this helped. A brainliest would be very much appreciated. (I need 4 brainliest so I can level up) :)

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Brielle and Joshua are running a half marathon race, which is 13.1 miles long. It takes Brielle 10 minutes to run 1.25 miles and
CaHeK987 [17]

Answer: Brielle will run the marathon faster.

Brielle = 104.8 minutes  

Joshua = 157.2 minutes

Step-by-step explanation:

Speed rate = distance /time

Brielle = 1.25 /10 = 0.125 miles per minute

Joshua = 1.5/18 = 0.083333 =1/12 miles per minute

Since 0.125 (Brielle) > 1/12 (Joshua)

Brielle will run the marathon faster.

To calculate the time that takes each one to run the entire race (13.1 miles)

Time= distance / speed

  • Brielle = 13.1 /0.125 = 104.8 minutes
  • Joshua = 13.1 / (1/12)= 157.2 minutes

Feel free to ask for more if needed or if you did not understand something.

8 0
3 years ago
David is filling out orders for an online business and gets paid $1 for each order he fills out plus bonus of 25 cents per order
svp [43]

Answer:

David will make $481 (he earns the bonus)

Explanation:

<em>If he makes $1 for each order and he filled out 385 orders, then why can't we say he made $385?</em>

Because of this statement rights here:

"...and gets paid $1 for each order he fills out plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20."

So we need to find out if any of the 3 weeks has an average of 20+ orders per day.

<h2>David is filling out orders for an online business and gets paid $1 for each order he fills out</h2>

(x is the amount of orders he fills out)

profit = $1x

<h2>plus bonus of 25 cents per order if the average number of orders he completes per day within any of the given weeks exceeds 20. </h2>

if any average orders per day is > 20 in any week

bonus profit = $1.25x

<h2>The ratio of the number of orders he processed during the first week to the number of orders he processed during the second week is 3:2, </h2>

first week     second week

             3a : 2a

<h2>while the the ratio that compares the number of orders he filled out during the first and the third weeks is 4 to 5 respectively. </h2>

first week   third week

           4a : 5a

<h2>What amount of money will David make at the end of three weeks if the total number of orders he filled out was 385?</h2>

sum of all ratios of a = 385

So we have

3a : <u>2a</u> (first week to <u>second week</u>)

4a : <em>5a </em>(first week to <em>third week</em>)

Notice how the first two numbers are both from the first week. Let's use the Least Common Multiple to make them equal while still keeping ratios.

LCM of 3 and 4: 12 = 3 * 4

12a : <u>8a</u> ( times 4 )

12a : <em>15a</em> ( times 3 )

Now that we have the same value, we can create a big ratio

first week <u>second week</u> <em>third week</em>

   12a     :        <u>8a</u>          :      <em>15a</em>

we know that these ratios will all equal 385. Since ratios are equal no matter how big we make them, we can say that

12a + <u>8</u>a + <em>15</em>a = 385 (a is a variable to scale up the ratio)

which is the same as

(12 + <u>8</u> + <em>15</em>) * a = 385

(<em><u>35</u></em>) * a = 385

35a = 385

if we solve for a by dividing 35 on both sides we get

a = 11

This gives us how much to multiply the RATIO by to get the ACTUAL NUMBER of orders completed. Let's plug 11 for 'a' and see what happens.

12a + <u>8</u>a + <em>15</em>a = 385

12(11) + <u>8</u>(11) + <em>15</em>(11) = 385

132 + <u>88</u> + <em>165</em> = 385     (Check that out, the number of orders each week!)

<u>220</u> + <em>165</em> = 385

<em><u>385</u></em> = 385

Bingo! All the math works out. So, looking back at the verryyy top of this problem, the reason why it wasn't as easy as $385 was because of the bonus.

The bonus gives David $1.25 per order instead of $1 per order if any of the weeks have an average ORDER PER DAY of anything bigger than 20. If we know the real numbers of orders for every week (132, <u>88</u>, and <em>165</em>), then we can divide it by 7 to get the average order per day. Let's choose <em>165 </em>(the <em>third week</em>) because it is the biggest and has the greatest chance of meeting our goal.

165 orders / 7 days (7 days in a week) = 23.57 orders per day

Is this greater than 20 orders per day?

YES!

So now we can safely say that the bonus is there or not, and in this case, the bonus IS there because there is a week where David had more than 20 orders per day.

So instead of using

profit = $1x

We will use

bonus profit = $1.25x

(x is the amount of orders completed)

So if we know he completed 385 orders, and we know he earned the bonus, we plug in 385 for x for the bonus function

bonus profit = $1.25x

bonus profit = $1.25 * 385

bonus profit = $481.25

If necessary, round your answer to the nearest dollar.

So for the very end, all we have to do is round it to the nearest dollar.

$481.25 rounds to $481.

And we're done!

8 0
3 years ago
PLZZZZZZZZZZZZZZZZ HELP ME!!!<br><br> 1 1/8 to decimal show your work!!!
lions [1.4K]

Answer:

1.125

Step-by-step explanation:

1) First you have to turn it into an improper fraction

8*1 = 8. Add the numerator--> 8+1 = 9.

2) The improper fraction is 9/8

3) Divide 9 by 8

 **Write this using long division

8 goes into 9 one time, so we will write one as our first digit

Carry down the 1 and the 0, 8 goes into 10 1 times so write 1.

And this point we have 1.1 above

Carry down the 2 and the 0, 8 goes into 20 2 times so write 2

At this point we have 1.12

Carry down the 4 and the 0, 8 goes into 40 5 times with no remainders so write 5 and end the division process.

Now we have 1.125 as our decimal for 9/8 which is equivalent to 1 1/8.

6 0
3 years ago
what is the diameter of 1e-5 meters? PLEASE GIVE ME THE RIGHT ANSWER I WILL MARK U AS BRAINLIEST... :)
joja [24]
I'm not sure exactly what you're asking but 1×10^-5 is .00001. I could be interpreting your question wrong in which case I'm sorry.
4 0
3 years ago
Help please!!!!!!!!!!!!!!!!!!!!!!!
nasty-shy [4]
Which question did you need help on?
4 0
3 years ago
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