She needs to lay 11 slabs on each row to make a square
<h3>How to determine the number of slabs in each row?</h3>
The total number of slabs is given as:
Total = 121 slabs
Let this represent the area of the slab.
The area of a square is calculated as:
Area = Length^2
Substitute the known values in the above equation
Length^2 = 121
Take the square root of both sides
Length = 11
Hence, she needs to lay 11 slabs on each row to make a square
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Answer:
option 2. 9.3+b=14.5
Step-by-step explanation:
I hope that the answer is clear
Are you missing information and or a picture that was provided?
Answer:
The ratio of the drag coefficients
is approximately 0.0002
Step-by-step explanation:
The given Reynolds number of the model = The Reynolds number of the prototype
The drag coefficient of the model,
= The drag coefficient of the prototype, 
The medium of the test for the model,
= The medium of the test for the prototype, 
The drag force is given as follows;

We have;

Therefore;







= (1/17)^3 ≈ 0.0002
The ratio of the drag coefficients
≈ 0.0002.
Answer:
i wrote this as a decimal so um i hope this at least helps :). 1.75
Step-by-step explanation: