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Rudiy27
2 years ago
15

FURNITURE A modern table is constructed with four legs made

Mathematics
1 answer:
Troyanec [42]2 years ago
7 0

The volume of a shape is the amount of space in it.

  • The expression that represents the volume of one table leg is: V = l^3 + n^3
  • The sides of the legs is 14.37 inches long

<u>(a) The volume of one table leg</u>

Represent the side length of the leg with l, and the side length of the notch with n.

So, the expression that represents the volume of one table leg is:

V = l^3 + n^3

<u>(b) The length of the sides</u>

From the question, we have:

n = 40\% \times l

Express 40% as decimal

n = 0.40 \times l

n = 0.4l

Substitute 0.4l for n in V = l^3 + n^3

V =l^3 + (0.4l)^3

V =l^3 + 0.064l^3

V =1.064l^3

The volume of the 4 legs is given as: 12636

So, the volume of one leg would be 12636/4

So, we have:

1.064l^3 = \frac{12636}{4}

1.064l^3 = 3159

Divide both sides by 1.064

l^3 = 2968.985

Take cube roots of both sides

l = 14.37

Hence, the sides of the legs is 14.37 inches long

Read more about volumes at:

brainly.com/question/1972490

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0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

Step-by-step explanation:

For each invoice, there are only two possible outcomes. Either they are paid within 10 working days, or they are not. The probability of an invoice being paid within 10 working days is independent of other invoices. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

60% of their invoices are paid within ten working days.

This means that p = 0.6

A random sample of 18 invoices is checked.

This means that n = 18

What is the probability that at least 6 of the invoices will be paid within ten working days?

Either less than 6 are paid within 10 working days, or at least 6 are paid. The sum of the probabilities of these events is 1. So

P(X < 6) + P(X \geq 6) = 1

We want P(X \geq 6). So

P(X \geq 6) = 1 - P(X < 6)

In which

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{18,0}.(0.6)^{0}.(0.4)^{18} \approx 0

P(X = 1) = C_{18,1}.(0.6)^{1}.(0.4)^{17} \approx 0

P(X = 2) = C_{18,2}.(0.6)^{2}.(0.4)^{16} \approx 0

P(X = 3) = C_{18,3}.(0.6)^{3}.(0.4)^{15} = 0.0002

P(X = 4) = C_{18,4}.(0.6)^{4}.(0.4)^{14} = 0.0011

P(X = 5) = C_{18,5}.(0.6)^{5}.(0.4)^{13} = 0.0045

P(X < 6) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0 + 0 + 0 + 0.0002 + 0.0011 + 0.0045 = 0.0058

Finally

P(X \geq 6) = 1 - P(X < 6) = 1 - 0.0058 = 0.9942

0.9942 = 99.42% probability that at least 6 of the invoices will be paid within ten working days

6 0
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