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aev [14]
3 years ago
12

The mat at the park is 30 feet wide. The mat is 6 feet longer than its wide. What is the area of the mat?

Mathematics
1 answer:
Greeley [361]3 years ago
4 0

The answer is 1,080.

Hope this helps!

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I would like to know what 1320 divided by 66 is
patriot [66]

 Q: 1320 divided by 66

A: Equals --> 20

Hopefully this helps ^0^ Mark Brain

8 0
3 years ago
What is the product of the rational expression 2/x+1 • 5/3x
mr_godi [17]

\left(\dfrac{2}{x+1}\right)\cdot\left(\dfrac{5}{3x}\right) = \dfrac{10}{3x^2+3x}

B is right

6 0
2 years ago
I need help with this math problem
Mkey [24]

Step-by-step explanation:

that is just a complicated way to ask, at what values of x is the functional value infinite ? or directly, for what values of x is the denominator of that fraction 0 ?

it is zero, if just one of the 3 factors is 0.

and that would happen for

x = 0

x = -6

x = 1

so, A, D and E are correct.

8 0
2 years ago
Find 15.75 ÷ 0.25 using a Giant One.
MA_775_DIABLO [31]

15.75 divided by 0.25

In every 1 whole number, there are 4 of 0.25

Now we have 15 as whole number so simply multiply 15 x 4

15 * 4 = 60, there are 60 pieces of .025s in 15.

0.75 has 3 0.25s  

Now, let’s add 60 + 3 = 63, the answer is 63.

There are 63 pieces of 0.25 in 15.75.

15.75 / 0.25

63


4 0
3 years ago
each of equal sides of an isosceles triangle is 4cm greater than its height .If the base of triangle is 24 cm ,calculate the per
Montano1993 [528]
<h3><u>Answer</u><u>:</u><u>-</u></h3>

192 cm²

<h3><u>Step</u><u> </u><u>by</u><u> step</u><u> explanation</u><u> </u><u>:</u><u>-</u></h3>

Let us take the height be x , then its side = x + 4. Now half of base will be 12 cm .

<u>According</u><u> to Pythagoras Theorem :- </u>

=> base² + perpendicular ² = hypontenuse ²

=> 12² + x² = (x+4)²

=> 144 + x² = x² + 16 + 8x

=> 8x = 144-16

=> 8x = 128

=> x = 128/8

=> x = 16 cm .

Hence the height of ∆ is 16 cm .So the area will be half the product of base and altitude.

= 1/2 * 16 cm * 24cm .

= 192 cm²

<h3><u>★</u><u> </u><u>Hence</u><u> </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>the </u><u>tria</u><u>ngle</u><u> is</u><u> </u><u>1</u><u>9</u><u>2</u><u> </u><u>cm²</u><u> </u><u>.</u></h3>
8 0
2 years ago
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