Answer:
B. 200 mm²
Step-by-step explanation:
The area of a rectangle part of the figure is found using length x width, which in this case is 25 x 2 = 50 mm²
The area of a triangle is found using . Since the values given are the legs that make up the right angle, your base and height are 15 mm and 20 mm. This means the area is , which is 150 mm².
The area of the figure as is whole is 50 + 150, which is 200 mm².
Answer:
then r is parallel to s
Step-by-step explanation:
<3 = <11
The are same side interior angles
If same side interior angles are equal , then r is parallel to s
Answer:
x = 12
Step-by-step explanation:
By applying Pythagoras theorem in the given right triangle,
(Hypotenuse)² = (leg 1)² + (leg 2)²
From the picture attached,
Length of Hypotenuse = 13
Length of leg 1 = 5
Length of leg 2 = x
By substituting these values in the formula,
(13)² = 5² + x²
169 = 25 + x²
169 - 25 = x²
144 = x²
(12)² = x²
x = 12
Answer:
B)
Step-by-step explanation:
The range is the lowest point to the highest point on the graph.
Remember this:
1. domain (x-axis) LEFT –> RIGHT
2. range BOTTOM (y-axis) –> TOP
when this equation is graphed over the domain, it limits the range to being (8,–5) and (–8,–1) and since with range you only look at the y-coordinates that means that the range is [–5,–1]
Answer:
Ok, "steeper than y = x^2" means that the function grows "faster" than y = x^2. and we can look at this by looking at the derivates, if the derivate is larger, then it is steeper.
The derivate of y = x^2 is: y´= 2x.
Now let's look at the other functions.
a) y = (1/2)*x^2
the derivate is:
y' = 2*(1/2)*x = x
this function is less steep than y = x^2
b) y = -x^2
the derivate is:
y' = -2x
So we have, in absolut value, exactly the same than for y = x^2.
The difference is that here the function decays instead of growing, so this is "less steep than y = x^2)
c) y = (2x)^2 = 4*x^2
the derivate is:
y´= 2*4*x = 8*x
this is steeper than y = x^2-
d) y = 2x^2
the derivate is:
y´= 2*2*x = 4x.
this is steeper than y = x^2
e) y = (x/2)^2 = (1/4)*x^2
the derivat is:
y' = (2/4)*x = (1/2)*x
so this is lees steep than y = x^2