Answer:
what
Step-by-step explanation:
Answer:
A = 16
Step-by-step explanation:
subtract .5 for both sides --> .25a = 4.5 - .5
.25a = 4
now divide .25 by both sides
A = 16
Assume that the data for both movies and basketball games are normally distributed.
Therefore, the median and the mean are assumed equal.
The standard deviation, σ, is related to the interquartile range by
IQR = 1.35
From the data, we can say the following:
Movies:
Range = 150 - 60 = 90 (approx)
Q1 = 62 (approx), first quartile
Q3 = 120 (approx), third quartlie
Q2 (median) = 90 (approx)
IQR = Q3 - Q1 = 58
σ = IQR/1.35 = 58/1.35 = 43
Basketball:
Range = 150 - 90 = 60 approx
Q1 = 95 (approx)
Q3 = 145 (approx)
Q2 = 125 (approx)
IQR = 145 - 95 = 50
σ = 50/1.35 = 37
Test the given answers.
A. The IQRs are approximately equal, so they are not good measures of spread. This is not a good answer.
B. The std. deviation is a better measure of spread for basketball. This is not a good answer.
C. IQR is not a better measure of spread for basketball games. This is not a good answer.
D. The standard deviation is a good measure of spread for both movies and basketball. This is the best answer.
Answer: D
Answer:
x = 15
Step-by-step explanation:
From the above diagram, we can see that the right angled triangle has been split into two by drawing a line from the altitude.
This would really in the following ratios or proportions below
25 : x = x : 9
25/x = x/9
Cross Multiply
x² = 25 × 9
x² = 225
x = √225
x = 15
