Answer:
40 minutes.
Step-by-step explanation:
- time spent on the thread mill as a function of d(day) = t(d)
= 30 +2(d-1) minutes
[where d represents day number]
(when d is 1 the time spent should be 30
so substitute d=1 and check it will be 30 only.
on first day he will spend 30 minutes so, I added 30 .
and on every additional day( these additional days are excluding first day), he will increase the time by 2 minutes.so, I added 2(d-1) to initial 30 minutes)
- so, T(6), the minutes he will spend on the treadmill on day 6=
=30+2(6-1)
=30+2(5)
=30+10
=40 minutes
<h3>
Answer: C) -1/2</h3>
=============================================
Explanation:
We'll apply the derivative to get
g(x) = 4x^3 + 3x^2
g ' (x) = 3*4x^2 + 2*3x
g ' (x) = 12x^2 + 6x
Set that equal to 0 and solve for x. We do this to find where the horizontal tangents are located.
g ' (x) = 0
12x^2 + 6x = 0
6x(2x + 1) = 0
6x = 0 or 2x+1 = 0
x = 0 or x = -1/2
Adding those two said solutions yields us the final answer choice C
Answer:
b = 12.6
Step-by-step explanation:
a*2 + b*2 = c*2
6*2 + b*2 = 14*2
36 + b*2 = 196
Subtract 36 from both sides
36 + b*2 = 196
-36 -36
b*2 = 160
Find the square root of both
b = 12.64911064 or 12.6
L=length W=width
perimeter=2Lx2W
196=2L+2W
Length can be written as 6W because it is 6 times the width. We then substitute this in so all the terms are the same
196=2(6W)+2W
196=12W+2W
196=14W
W=14cm
L= (14x6) 84cm
-2= y-4
——
0-2
-2= y-4
——
-2
(y-4)•-2 = -2
-2y+8=-2
-2y=-10
————
-2
y=5
hope this helps
