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grandymaker [24]
4 years ago
15

6 x 1 x 5 x 1/10 as a decimal

Mathematics
1 answer:
saveliy_v [14]4 years ago
4 0

Answer:

30.10

Step-by-step explanation:

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Help!
Bess [88]
Website 1

y=1.50x+30

Website 2

y=2x+30

Hope this helps!
4 0
3 years ago
What is the solution to the system of equations?
algol [13]
20 divided by 3 is 998
3 0
3 years ago
How did you apply proportional reasoning as you worked through these problems?
pogonyaev

Answer:

youll have to show the problems to get an answer!

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Please help me with these, oh sweet jesus
Lelechka [254]

Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

78.  \sec^{4}x \tan^{2} x = \sec^{2}x [\tan^{2}x + \tan^{4}x ] Proved

79. \cos^{3} x\sin^{2} x = [\sin^{2}x - \sin^{4}x] \cos x Proved.

80. \sin^{4}x - \cos^{4}x = 1 - 2\cos^{2}x + 2 \cos^{4} x Proved.

Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

= Right hand side (Proved)

78. Left hand side

= \sec^{4}x \tan^{2} x

= \sec^{2} x [1 + \tan^{2}x] \tan^{2} x  

{Since \sec^{2}x - \tan^{2}x = 1}

= \sec^{2}x [\tan^{2}x + \tan^{4}x ]

= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

= \cos x[1 - \sin^{2} x] \sin^{2} x

{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

= Right hand side

80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

= Right hand side. (Proved)

7 0
3 years ago
In the set of real numbers, the first number less than -3 is -4. True False
mariarad [96]
True, -4 seems bigger because 4 is bigger than 3 but it's negative and is further away from 0 
6 0
3 years ago
Read 2 more answers
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