Answer:
see explanation
Step-by-step explanation:
To show f and g are inverses we require to show that
f(g(x)) = x and g(f(x)) = x
f(g(x))
= f(6x - 4)
= 
= 
= x
-----------------------------------------------------------------------------
g(f(x))
= g(
)
= ( 6 × ) - 4
= x + 4 - 4 = x
-------------------------------------------------
Hence f and g are inverses
The most right answer would be the one you think because I think that’s right 4x4
The absolute value of zero is zero
The equation is
.
We are looking for a function with a vertex above the x-axis and a function that opens upward (has coefficient a > 0).
The first function opens downward and intersects the x-axis. The second function has a vertex below the x-axis. The third function satisfies our requirements. The fourth function has a vertex on the x-axis.
We can solve this algebraically with the knowledge that the real solutions of a quadratic are its x-intercepts. If there are no x-intercepts (because it lies entirely above or below the x-axis), then there are no real solutions. This is true when the discriminant
. You can see that from the quadratic formula. This holds true for both answers A and C, so to find the correct one, we remember that when the coefficient a of the
term is positive, the graph opens upwards, so we choose
C.
Answer:
(cos^2 y) /(1-sin y) = (1 - sin^2 y) / (1-sin y) = ((1-sin y)(1+sin y)) / (1-sin y) = 1+sin y
