Question

PLS HELP ITS A MAJOR GRADE AND DUE TOMORROW

Answer 1

Answer:

*See below*

Step-by-step explanation:

Identify and Explain Error

The method shown is using fractions to compare costs. This strategy does not work due to the fact that they have not factored in the $55 he pays for the car before hand. Also, 150 divided by 0.5 does not equal 30, it equals 300 so, even if he did not pay $55 beforehand, the equation is still incorrect.

Correct Work/Solution

$55 to rent

$0.50 per mile

Let's start by removing $55 from $150 to see how many dollars is left over for gas.

150 - 55 = 95

Then, divide 95 by 0.5

95 ÷ 0.5 = 190

He can drive at least 190 miles.

Share Strategy

Since he starts off paying $55 dollars out of $150, we need to subtract $55 by $150 to see how much cash he has left over for mileage. $150 minus $55 equals $95 so, he has $95 left over for mileage. $95 will then be divided by $0.50 to find out how many miles he can drive. We are dividing by $0.50 because that's the cost per mile. $95 divided by $0.50 equals 190 so he can drive at least 190 miles.

Note:

Hope this helps :)

Have a great day!