It should be noted that No. the value of the 9 in the hundred place is not ten times the value of 3 in the tens place.
<h3>How to illustrate the information?</h3>
It should be noted that the value of 3 in 1934 is 30 and the value of 9 is 900.
1934 = 1000 + 900 + 30 + 4
Therefore the value of 9 will be:
= 30 × 3
Therefore, the the value of the 9 in the hundred place is 30 times the value of 3 in the tens place.
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Answer:
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
5)
Adj = 14
Hyp = 26
∠X
so use
CAH
Cos(X) = 14/26
X = arcCos(14/26)
X = 57.421°
X = 57.4 ° ( rounded to nearest 10th )
6)
∠X
Hyp = 46
Opp = 12
use SOH
Sin(x) = 12/46
X = arcSin(12/46)
X = 15.121°
X = 15.1 ° ( rounded to nearest 10th )
7)
∠X
Adj = 29
Opp = 24
use TOA
Tan(x) = 29 / 24
X = arcTan( 29 /24)
X = 50.389
X = 50.4 ° ( rounded to nearest 10th )
8)
∠X
Adj = 22
Opp = 6
use TOA agian
Tan(x) = 6 / 22
X = arcTan(6/22)
X = 5.194
X = 5.2 ° ( rounded to the nearest 10th )
:)
Part 1:
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:

Now,

Therefore, the radius of the circle is
10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then

Now,

Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:

Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately
12.9 cm.