Answer:
I honestly don't know if you're being serious or not as this was a popular thing a few years ago, there are a few videos on yt, one particularly from 2008 that answers your question pretty well.
Clipping through a loading area requires at least 400 speed. But if you're just interested in the usual speed, there are multiple glitches to make him go faster than his usual x3.5 increased running speed (which is the speed you get at the LEAST when BLJing) but it seems the average is -200. I've seen people get up to -900 though, so.
Basically, it can vary. In a very specific area he can get max momentum of -9373, which is probably the fastest even though it's against a wall.
Answer:
B. Which customer most frequently purchases bread.
Explanation:
As per the scenario, the data we are receiving from the sales record of the bakery is :
The date on which the items are sold
Each items name which are sold
The number of each item sold and
The price of each item sold
These data are required to estimate how much the company has earned the profit during a given period of time.
So from the above scenario, there is no data given about the customer i.e customer name, customer number, etc. So there is no chance to track the details of a customer purchase history.
Therefore, the most appropriate answer is option B
They should be between 1 and 1/4 inches
We have that the .xlsm <em>Format </em>is used to save Excel Macro-Enabled Workbook file
<h3>Formats</h3>
Generally file are saved in different formats for easy sorting and application on the operating system.
For instance if a music file is renamed and stored in a different format say .exe the audio file wont be recognised as an audio file and hence refuse to play.
e.g
- .exe for a windows appication
- ,mp3 for an audio file
- .xlsm here is used to save Excel Macro-Enabled Workbook file
For more information on Excel visit
brainly.com/question/19295387
Answer:
#include <iostream>
using namespace std;
double DrivingCost(int drivenMiles,double milesPerGallon,double dollarsPerGallon)
{
double dollarsperMile=dollarsPerGallon/milesPerGallon;//calculating dollarsperMile.
return dollarsperMile*drivenMiles;//returning thr driving cost..
}
int main() {
double ans;
int miles;
cout<<"Enter miles"<<endl;
cin>>miles;
ans=DrivingCost(miles,20.0,3.1599);
cout<<ans<<endl;
return 0;
}
Output:-
Enter miles
10
1.57995
Enter miles
50
7.89975
Enter miles
100
15.7995
Explanation:
In the function first I have calculated the dollars per mile and after that I have returned the product of dollarspermile and driven miles.This will give the cost of the Driving.
