The equation of the line which passes through the point (-5, 3) and is parallel to the equation 3x -5y = 30 is; 3x -5y = 30.
<h3>What is the equation of the line?</h3>
Since the line is parallel to the given line; 3x -5y = 30 whose slope is; 3/5.
Hence, since the two lines have equal slopes;
3/5 = (y-3)/(x-(-5))
3/5 = (y-3)/(x+5)
5y -15 = 3x +15
3x -5y = 30
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By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
<h3>How to determine the maximum height of the ball</h3>
Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:
- 4.8 · t² + 19.9 · t + (55.3 - h) = 0
The height of the ball is a maximum when the discriminant is equal to zero:
19.9² - 4 · (- 4.8) · (55.3 - h) = 0
396.01 + 19.2 · (55.3 - h) = 0
19.2 · (55.3 - h) = -396.01
55.3 - h = -20.626
h = 55.3 + 20.626
h = 75.926 m
By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.
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the angle 4pi/5 in quadrent 2
Time = Distance / Speed [ Already mentioned ]
Then, substitute the known values,
t = (9.6 × 10⁶) / (3 × 10⁸)
t = 3.2 × 10⁻² s
In short, Your Answer would be Option B
Hope this helps!
Answer:
your answer is b bud... your welcome....
Step-by-step explanation:
just took the test
