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2 years ago

Help please, help please

Mathematics

1 answer:

coldgirl [10]2 years ago

6 0

Answer:

i think the perimeter is 60

Step-by-step explanation:

9²+12² = x²

15 = x

perimeter = 15×4 = 60

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I NEED HELP, JUST LOOK AT THE PICTURE I ATTACHED

NISA [10]

Answer:

Step-by-step explanation:

there are 15 pieces of candy and 5 people, so all you have to do is divided 15 by 5 which gives you 3 meaning each person gets 3 pieces.

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5 months ago

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The product of two numbers is 30. One of the numbers is t. What expression represents the other number?

Alexandra [31]

t * x = 30

Or, 30 / t = x

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3 years ago

I need the answer ASAP anyone could help me please

cupoosta [38]

Answer:

Is it the answer is C?

2+4+3+5+1=15

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2 years ago

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Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

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2 years ago

WILL CHOOSE BRAINLIEST!!! Quadrilateral ABCD is congruent to quadrilateral RSTU. Without seeing the figures visually, which stat

garri49 [273]

2nd option

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1 year ago

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