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m_a_m_a [10]
3 years ago
7

Help me with my math please, it’s 6th grade

Mathematics
1 answer:
sashaice [31]3 years ago
8 0
The one that has -7 and -13 on the first line.

Itd be the 2nd answer from the top.
You might be interested in
Find polar coordinates of the point whose cartesian coordinates are given. (-2√3 , 2)
gavmur [86]

The  polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)

<h3>Polar form of a rectangular coordinate</h3>

The polar form of a rectangular coordinate (x, y) is expressed as (rcos theta, r sin theta)

Given the coordinate (-2√3 , 2)

r = √(-2√3)²+2²

r = √12+4

r = 4

theta = tan^-1(-2/2√3)

theta = tan^-1(-1/√3)

theta = -30 degrees = 210 degrees

The  polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)

Learn more on polar coordinate here: brainly.com/question/14965899

#SPJ1

8 0
1 year ago
Solve the equation.
DENIUS [597]
Hello :)

11,3x+7,2=86,3
⇔11,3x=86,3-7,2=79,1
⇔x=79,1/11,3= 7

The answers is c) 7 :). 

6 0
3 years ago
Read 2 more answers
The number of Atlantic blue fin tuna in thousands can be modeled by P(x)=230(.881)^x where X represents the number of years sinc
Maurinko [17]
<h3>Answer: 1981</h3>

===================================

Work Shown:

Recall that P is in thousands, so P = 95 means 95,000.

Plug in P(x) = 95. Solve for x. Use logarithms to get this done.

P(x)=230(0.881)^x

95=230(0.881)^x

95/230 = (0.881)^x

0.41304347826087 = (0.881)^x

(0.881)^x = 0.41304347826087

Log( (0.881)^x )= Log( 0.41304347826087 )

x*Log( 0.881 )= Log( 0.41304347826087 )

x= Log( 0.41304347826087 )/Log( 0.881 )

x= 6.97883817154785

x= 7

Approximately 7 years after 1974 is when the population will be around 95,000.

7 years after 1974 = 1974+7 = 1981

8 0
3 years ago
Please help me out here I'm failing math.
natulia [17]

Answer:

-4r - 11 = 4r + 21

-4r -4r = 21 + 11

-8 = 32 (Divide both sides by -8)

/ /

-8 -8

= -4

8 0
3 years ago
BRAINLIEST!!!
Sonbull [250]

Answer:

\sqrt{37}

Step-by-step explanation:

The distance d between a point (m , n ) and a line in the form

Ax + By + C = 0 , is calculated as

d = \frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }

Here (m, n ) = (6, 2 ) and

6x - y = - 3 ( add 3 to both sides )

6x - y + 3 = 0 → A = 6, B = - 1, C = 3

d = \frac{|6(6)+-1(2)+3|}{\sqrt{6^2+(-1)^2} }

   = \frac{|36-2+3|}{\sqrt{36+1} }

   = \frac{|37|}{\sqrt{37} }

   = \frac{37}{\sqrt{37} } × \frac{\sqrt{37} }{\sqrt{37} }

   = \frac{37\sqrt{37} }{37} ← cancel 37 on numerator/ denominator

   = \sqrt{37}

7 0
3 years ago
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