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avanturin [10]
3 years ago
6

ABAC -A DEC

Mathematics
1 answer:
garri49 [273]3 years ago
6 0

Answer:

31.5/15 = 2.1

2.1 x 18 =37.8

Check by Soh Cah Toa

1) Tan-(15/18)=40* to 1d.p for angle ACB

Tan-(18/15)=50* to 1d.p for angle ABC

40 + 50=90

90+90 (in the right angled triangle) =180*

Angle in triangle add to 180

Let's check for the big triangle:

Opposite angles are equal. So, DCE is 40.

DE is opposite, x is adjacent.

Tan(40) = o/a

=31.5/x

Multiply by x both side

Tan(40) multiply by x = 31.5

Divide by Tan(40) both side and get x on its own.

x=31.5/Tan(40)

= 37.54023817.

So, x = 37.5 to 1 d.p

Pythag to fin hypotenuse of both triangle and divided by each other to see if it matches decimal multiplier at the start of my solution.

49/23=2.1 (all values to 1d.p)

Also, 37.5/18 = 2.1 to 1 d.p

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