All categories

3 years ago

I need help 3-6 pleasr

Mathematics

1 answer:

Colt1911 [192]3 years ago

4 0

3) Mathematical expression would be:
412 - 65 + 0.50x
Where, x = Number of Texts sent

4) Product means result after multiplication, sum after addition, quotient is the result of division with remainder, and difference is how far two numbers are in their magnitude.
"Per" tells us the magnitude for an Unit value.

5) Associative property = (a+b) + c = a+ (b+c)
Commutative property = a + b = b + a
Distributive Property = a(b+c) = ab+bc

They all have their unique characteristics and can be differentiated on that basis.

6) They all are same.
At the end, without parentheses and in proper symbol, it would be equal to -3/4

Hope this helps!

You might be interested in

Given the definitions of f(x) and g(x) below, find the value of g(f(6)).

Fofino [41]

3 because it is a better Dona a toon

8 0

3 years ago

I need help with this question. Can someone help me with it? And show work!

kondor19780726 [428]

Answer:

Step-by-step explanation:

K=1/3=10

L=1/5=6

10+6=16

30-16=14

4 0

4 years ago

Read 2 more answers

"Two purple sea slugs are mated with each other. Among their numerous offspring, 428 have a purple integument and 152 have orang

Orlov [11]

Answer:55

Step-by-step explanation:

55x1=55

6 0

3 years ago

A bag contains 15 red candies, 15 yellow candies, and 15 blue candies. What is the probability of randomly

masya89 [10]

$|\Omega|=45\cdot44=1980\\|A|=15\cdot14\cdot3=630\\\\P(A)=\dfrac{630}{1980}=\dfrac{7}{22}\approx31.8\%$

6 0

2 years ago

Someone help please

Alla [95]

Answer: Choice A

$\tan(\alpha)*\cot^2(\alpha)\\\\$

============================================================

Explanation:

Recall that $\tan(x) = \frac{\sin(x)}{\cos(x)}$ and $\cot(x) = \frac{\cos(x)}{\sin(x)}$ . The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

$\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\$

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why $\tan(\alpha)*\cot^2(\alpha)\\\\$ is identical to $\frac{\cos(\alpha)}{\sin(\alpha)}\\\\$

Therefore, $\tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\$ is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that $\tan(\alpha)*\cot^2(\alpha)\\\\$ is the same as $\frac{\cos(\alpha)}{\sin(\alpha)}\\\\$ by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

6 0

3 years ago