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Ilya [14]
3 years ago
7

There are two consecutive odd integers. The

Mathematics
1 answer:
kifflom [539]3 years ago
3 0

Answer:

  13, 15

Step-by-step explanation:

Let x represent the smaller of the two integers. Then the larger is x+2. The required relation is ...

  x² = 154 +(x +2) . . . . . . the smaller squared is 154 more than the larger

  x² -x = 156 . . . . . . . . . . subtract x

  x² -x +1/4 = 156.25 . . . complete the square

  (x -1/2) = √156.25 = 12.5 . . . . take the square root

  x = 13 . . . . . add 1/2

The two integers are 13 and 15.

__

<em>Check</em>

  13² -15 = 169 -15 = 154 . . . as required

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2 1/4 pounds are left of the clay :)
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3 years ago
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In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g
KIM [24]

Answer:

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

All girls from the first group:

20 students, so N = 20

10 girls, so k = 10

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163

All girls from the second group:

20 students, so N = 20

5 girls, so k = 5

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006

All girls from the third group:

20 students, so N = 20

8 girls, so k = 8

5 students will be selected, so n = 5

We want all of them to be girls, so we find P(X = 5).

P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}

3.52 \times 10^{-9} = 3.52 \times 10^{-7}\% probability that all the 15 students selected are girls

7 0
3 years ago
1. A pack with 6 cans of juice costs $3.48. What is the unit rate?
Mrac [35]
Hey!~

The correct answer is C, $0.58 per can. You were right!
$3.48/6=$0.58.

Hope this helps and have a great day!

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4 0
3 years ago
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a square and an equilateral triangle have the same perimeter. Each side on the triangle is 1 inch longer than the side of the sq
Otrada [13]

Answer:

48 inches

Step-by-step explanation:

Given:

A square and an equilateral triangle have the same perimeter

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What to find:

What is the perimeter of the square =?

Solution:

Let the side of the square be  

Then the side of the triangle will be  

The Perimeter of square = Perimeter of an equilateral triangle

=  

Subtracting both sides by  

side of the square,  = 12 inches

side of triangle will be , 12 + 4 = 16 inches

Now, the perimeter of the square =  

Therefore, the perimeter of the square is 48 inches.

and your pfp is so cute!!

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3 years ago
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Natali5045456 [20]
i think its C, 204 units
5 0
3 years ago
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