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2 years ago

Find the prime factors of given numbers and express them in exponential form. a) 243 b) 1331 c)343

Mathematics

1 answer:

AveGali [126]2 years ago

4 0

a) 243= 3⁵

b) 1331= 11³

c) 343= 7³

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3 years ago

Simplify 3x+6=18, please

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3 years ago

Read 2 more answers

Simplify the expression.<br> -5+i/2i

Lostsunrise [7]

Answer:

$\rm - \dfrac{11}{2}$

Step-by-step explanation:

$\rm Simplify \: the \: following: \\ \rm \longrightarrow - 5 + \dfrac{i}{2} i \\ \\ \rm Combine \: powers. \\ \rm \dfrac{i \times i}{2} = \dfrac{i^{1 + 1}}{2}: \\ \rm \longrightarrow - 5 + \dfrac{i^{1 + 1}}{2} \\ \\ \rm 1 + 1 = 2: \\ \rm \longrightarrow - 5 + \dfrac{i^2}{2} \\ \\ \rm i^2 = -1: \\ \rm \longrightarrow - 5 + \dfrac{( - 1)}{2} \\ \\ \rm \longrightarrow - 5 - \dfrac{1}{2} \\ \\ \rm Put \: - 5 - \dfrac{1}{2} \: over \: the \: common \: denominator \: 2. \\ \rm - 5 - \dfrac{1}{2} = \dfrac{2( - 5)}{2} - \dfrac{1}{2} : \\ \rm \longrightarrow \dfrac{ - 5 \times 2}{2} - \dfrac{1}{2} \\ \\ \rm 2 (-5) = -10: \\ \rm \longrightarrow \dfrac{ - 10}{2} - \dfrac{1}{2} \\ \\ \rm \dfrac{ - 10}{2} - \dfrac{1}{2} = \dfrac{ - 10 - 1}{2} : \\ \rm \longrightarrow \dfrac{ - 10 - 1}{2} \\ \\ \rm -10 - 1 = -11: \\ \rm \longrightarrow - \dfrac{11}{2}$

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3 years ago

If (x + 2) is a factor of x3 − 6x2 + kx + 10, k =

ch4aika [34]

Answer:

The value of k is -11

Step-by-step explanation:

If (x+2) is a factor of x3 − 6x2 + kx + 10:

Then,

f(x)=x3 − 6x2 + kx + 10

f(-2)=0

f(-2)=(-2)³-6(-2)²+k(-2)+10=0

f(-2)= -8-6(4)-2k+10=0

f(-2)= -8-24-2k+10=0

Solve the like terms:

f(-2)=-2k-22=0

f(-2)=-2k=0+22

-2k=22

k=22/-2

k=-11

Hence the value of k is -11....

5 0

3 years ago

Find the prime factors of given numbers and express them in exponential form. a) 243 b) 1331 c)343​

Find the prime factors of given numbers and express them in exponential form. a) 243 b) 1331 c)343