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zzz [600]
2 years ago
9

f(x) = 3/4 * x - 7 . Find x if f(x) = - 1 . PLEASE tell how to solve it bc that what i dont know, i dont want just the answer​

Mathematics
1 answer:
Eva8 [605]2 years ago
8 0

Answer:

x=-8 if f(x)=-1

Step-by-step explanation:

Given --> f(x)=-\frac{3}{4}x-7

Substitute f(x)=-1 into the equation and solve for x:

-1=-\frac{3}{4}x-7

6=-\frac{3}{4}x

24=-3x

-8=x

So, when f(x)=-1,x=-8

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Geometry, dont need explanation. Just those 3 questions.
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Answer:

1. B

2. A

3. C

Step-by-step explanation:

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2 years ago
Please help me<br> thanks
attashe74 [19]

..no lo sé, pero como necesito puntos, ¿sí?

6 0
2 years ago
I dont understand this please help​
Alex787 [66]

Answer:

Its asking you which one is greater or less than. Hope this help?

Step-by-step explanation:

6 0
4 years ago
2x^3=28<br><br> find the exact solution for x
Alborosie

Answer:

The answer to your question is:  x = 2.41

Step-by-step explanation:

                                            2x³ = 28

                                             x³ = 28/2

                                             x³ = 14

                                             x = ∛14

                                            x = 2.41

6 0
3 years ago
Which of the following is NOT a linear factor of the polynomial function?
Natalija [7]

Answer:

Among the four choices, (x + 5) is the only one that is not a linear factor of this polynomial function.

Step-by-step explanation:

Let a denote some constant. A linear factor of the form (x - a) is a factor of a polynomial f(x) if and only if f(a) = 0 (that is: replacing all x in the polynomial f(x) \! with the constant a\! would give this polynomial a value of 0.)

For example, in the second linear factor (x - 2), the value of the constant is a = 2. Verify that the value of f(2) is indeed 0. (In other words, replacing all x in the polynomial f(x) \! with the constant 2 should give this polynomial a value of 0\!.)

\begin{aligned}f(2) &= 2^3 - 5\times 2^2 - 4 \times 2 + 20 \\ &= 8 - 20 - 8 + 20 \\ &= 0 \end{aligned}.

Hence, (x - 2) is indeed a linear factor of polynomial f(x).

Similarly, it could be verified that (x - 5) and (x + 2) are also linear factors of this polynomial function.

Rewrite the first linear factor (x + 5) in the form (x - a) for some constant a: (x + 5) = (x - (-5)), where a = -5.

Calculate the value of f(5).

\begin{aligned}f(5) &= (-5)^3 - 5\times (-5)^2 - 4 \times (-5) + 20 \\ &= (-125) - 125 + 20 + 20 \\ &= -210\end{aligned}.

f(5) \ne 0 implies that (x - (-5)) (which is equivalent to (x + 5)) isn't a linear factor of this polynomial function.

3 0
3 years ago
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