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Kryger [21]
2 years ago
9

Please help me thanks

Mathematics
1 answer:
attashe74 [19]2 years ago
6 0

..no lo sé, pero como necesito puntos, ¿sí?

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PLEASE HELP ME WITH THIS THANKS
stich3 [128]

Answer:

The answer to your question is Volume = 12735.06 cm³

Step-by-step explanation:

Data

a = 11.26 cm

s = 13 cm

h = 29 cm

Formula

V = BH

Process

1.- Calculate the area of the base

Area = B = Pa/2

P = Perimeter

P = 6(13)

P = 78 cm

Area = (78)(11.26)/2

        = 878.28/2

       = 439.14 cm²

2.- Calculate the volume

Volume = BH

             = (439.14)(29)

             = 12735.06 cm³

7 0
3 years ago
Read 2 more answers
Solve for x.<br> X + 10<br> 2x - 50<br><br> x = [?]
Vladimir [108]

Answer:

x +10 = 2x-50

x-2x = -50-10

-x. = -60

-x/-1 = -60/-1

x = 60°

6 0
3 years ago
what is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)
riadik2000 [5.3K]

Answer:

y = -\frac53x + 20

Step-by-step explanation:

Hello!

A line that is perpendicular to another has an opposite-reciprocal slope.

Meaning:

  • Flip the sign (+/-)
  • Flip the fraction

The slope perpendicular to 3/5 would be -5/3.

We can solve for the y-intercept by plugging in the x and y values given from the coordinate into the equation with out new slope.

<h3 /><h3>Solve for B</h3>
  • y = -\frac53x + b
  • -5 = -\frac53(15) + b
  • -5 = -25 + b
  • 20 = b

The y-intercept of the new line is 20.

The equation is y = -\frac53x + 20

6 0
2 years ago
what is the curvature of my B I G Bal ls are they are stroking your face while you su ck my a n us? What is 5 times 5?
salantis [7]
<span>Often the university sites exist primarily for internal use, listing equipment and demos available to physics professors teaching large sections of introductory courses. They usually give lists of required equipment, they don't always give much information about setup, effective presentation and explanation of the physics.</span>
7 0
2 years ago
If f(x)3(=- Vx-3, complete the following statement:x + 2f(19) ==Answer here
Digiron [165]
Explanation

This exercise is about evaluating a function at a particular argument. To do that, we replace the variable with the argument in the formula of the function, and simplify.

Let's do that:

\begin{gathered} f(19)=\frac{3}{19+2}-\sqrt[]{19-3}, \\  \\ f(19)=\frac{3}{21}-\sqrt[]{16}, \\  \\ f(19)=\frac{1}{7}-4, \\  \\ f(19)=\frac{1-28}{7}, \\  \\ f(19)=-\frac{27}{7}\text{.} \end{gathered}Answerf(19)=-\frac{27}{7}\text{.}

8 0
1 year ago
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