A. to find out if a hypothesis is correct.
Answer: 'At high fructose concentrations, respiration is inhibited while glycolytic end products accumulate, a phenomenon known as the Crabtree effect. It is commonly believed that this effect is restricted to microbial and tumour cells with uniquely high glycolytic capacities (Sussman et al, 1980).
Explanation: Sorry I dont really know a lot
Answer:
<h2>Recombination rate or recombination frequency between locus A and locus C is either 2% or 50%.
</h2>
Explanation:
As given,
Recombination frequency between locus A and B is 35%, means that the distance between A and B is 35 cM.
Recombination frequency between locus B and C is 33% , means the distance between B and C is 33 cM.
Therefore, if the locus C is present between A and B, then the recombination frequency between A and C would be 2%
A-----C ----------B
A---C= 2%
A----B= 35%
B---C= 33%
So, here the recombination frequency between A and C is 2%, means their distance is 2 cM.
If the locus C is as, A---35---B--33----C ; A-----B------C
A-----B= 35%
B------C= 33%
A-----C= 33+35= 68%
As rule, maximum frequency can not exceed 50%, as here the Recombination frequency between A and C = 50%.
The answer is pelvic outlet. It is because if this is not
large enough and it is small, the baby won’t be able to be carried or delivered
out from the woman’s vagina as it won’t fit the baby and will likely lead to
complications if pushed through.
