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Gnoma [55]
2 years ago
10

Simplify the following 2 √5 *5 √5

Mathematics
1 answer:
Wewaii [24]2 years ago
6 0

Answer: 50!!!

Step-by-step explanation:

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One shelf will hold 45 pounds of boxes. If you have to store 270 pounds of boxes, how many shelves will you need?
arlik [135]

Hi!

We will solve this using ratios, like this:

1 shelf holds 45 pounds

x shelves hold 270 pounds

______________________

x = (270*1)/45

x = 270/45

x = 6

6 shelves will be needed to hold 270 pounds of boxes.

Hope this helps!

6 0
3 years ago
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The binomial 8x+6 is equivalent to​
andreyandreev [35.5K]

Using the Distributive Property

The answer would be 3.

2 *4x = 8x and 2 * 3 = 6, to get 8x 6

5 0
3 years ago
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a first number is 6 more than a second number. the first number multiplied by 2 is 8 more than the second number. what are the t
Andreas93 [3]

Answer:

-2 (negative 2)

Step-by-step explanation:

8÷2 =4

4-6 = -2

hope this helps

4 0
2 years ago
Find the probability of the following events , when a dice is thrown once:
Fudgin [204]

Answer:

Step-by-step explanation:

s a die is rolled once, therefore there are six possible outcomes, i.e., 1,2,3,4,5,6.

(a) Let A be an event ''getting a prime number''.

Favourable cases for a prime number are 2,3,5,

i.e., n(A)=3

Hence P(A)=n(A)n(S)=36=12

(b) Let A be an event ''getting a number between 3 and 6''.

Favourable cases for events A are 4 or 5.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(c) Let A be an event ''a number greater than 4''.

Favourable cases of events A are 5, 6.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(d) Let A be the event of getting a number at most 4.

∴ A={1,2,3} ⇒ n(A)=4,n(S)=6

∴ Required probability =n(A)n(S)=42=23

(e) Let A be the event of getting a factor of 6.

∴ A={1,2,36} ⇒ n(A)=4,n(A)=6

∴ Required probability =46=23

(ii) Since, a pair of dice is thrown once, so there are 36 possible outcomes. i.e.,

(a) Let A be an event ''a total 6''. Favourable cases for a total of 6 are (2,4), (4,2), (3,3), (5,1), (1,5).

i.e., n(A)=5

Hence P(A)=n(A)n(S)=536

(b) Let A be an event ''a total of 10n. Favourable cases for total of 10 are (6,4), (4,6), (5,5).

i.e., n(A)=5

P(A)=n(A)n(S)=336=112

(c) Let A be an event ''the same number of the both the dice''. Favourable cases for same number on both dice are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).

i.e., n(A)=6

P(A)=n(A)n(S)=636=16

(d) Let A be an event ''of getting a total of 9''. Favourable cases for a total of 9 are (3,6), (6,3), (4,5), (5,4).

i.e., n(A)=4

P(A)=n(A)n(S)=436=19

(iii) We have, n(S) = 36

(a) Let A be an event ''a sum less than 7'' i.e., 2,3,4,5,6.

Favourable cases for a sum less than 7 ar

7 0
3 years ago
Read 2 more answers
What is 5/20 in its simplest form
notsponge [240]
5/20 in simplest form 

1) 5/20 can be divided by 5 

5 ÷ 5 = 1 
20 ÷ 5 = 4 

It cant be divided any more 

5/20 in simplest form is 1/4 
7 0
3 years ago
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