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nata0808 [166]
3 years ago
7

If PQ is tangent to circle R at point Q and PS is

Mathematics
1 answer:
Murljashka [212]3 years ago
3 0

Answer:

Perimeter of the quadrilateral PQRS is 25 units

Step-by-step explanation:

From the figure attached,

PQ is a tangent to the given circle so m∠PQR = 90°

Now we apply Pythagoras theorem in the ΔPQR,

PR² = PQ² + QR²

(PT + TR)²= PQ² + 5²

(4 + 5)² = PQ² + 25

81 = PQ² + 25

PQ = √(81 - 25)

     = √56

     ≈ 7.5 units

PQ ≅ PS ≅ 7.5 units

[Since measures of tangents drawn from a point to a circle are always equal]

Perimeter of PQRS = PQ + QR + RS + PS

                                = 7.5 + 5 + 5 + 7.5

                                = 25 units

Therefore, perimeter of the quadrilateral PQRS is 25 units.

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What is the least common denominator (LCD) of 12 and 23?
leva [86]

Answer: none of those, 276...?

Step-by-step explanation:

You need to know the least common denominator (LCD) of 12 and 23 if you want to add or subtract two fractions with 12 and 23 as denominators.

The least common denominator, also called lowest common denominator (LCD), of 12 and 23 is 276.

Here is a math problem example where you need to know the LCD of 12 and 23 to solve:

3/12 + 2/23 = ?

Step 1) Take the LCD and divide each denominator by it as follows:

276/12 = 23

276/23 = 12

Step 2) Multiply each nominator with the respective answers from Step 1:

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Step 3) Put it all together to solve the problem:

69/276 + 24/276 = 93/276

= 3/12 + 2/23 = 93/276

It's that easy! Once again, the lowest common denominator (LCD) of 12 and 23 is as follows:

276

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2 years ago
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3 years ago
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Step-by-step explanation:

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