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3 years ago

By which rule are these triangles congruent? АА SAS SSA AAS

Mathematics

2 answers:

vfiekz [6]3 years ago

8 0

Answer:

it's AAS is my opinion

Step-by-step explanation:

Mashutka [201]3 years ago

4 0

Answer:

AAS

Step-by-step explanation:

we can eliminate two of the answer choices from the start. AA and SSA do not prove triangle congruence. we are then left with SAS and AAS. we can see that there is one pair of sides and one pair of angles marked congruent on the triangles. the triangles are formed by intersecting lines which form vertical angles. according to the vertical angles theorem, those two angles will be congruent. therefore, these triangles are proven congruent by AAS. hope this helps!

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Let's say we have a triangle with sides called a, b, and c, and that b is the base. Our triangle has a height that we'll call h.

Irina18 [472]

Answer:

16.34 square inches.

Step-by-step explanation:

Given:

Base of triangle, b = 3 inches

Height of triangle, h = 10.89 inches

Question asked:

What is the area of this triangle in square inches?

Round your answer to the nearest hundredths place .

Solution:

As we know,

$Area\ of\ triangle =\frac{1}{2} \times base\times height$

$=\frac{1}{2} \times3\times10.89\\\\ =\frac{32.67}{2} \\\\ =16.335$

As, we have to find the answer to the nearest hundredths place, hence the area of triangle will be 16.34 square inches.

7 0

3 years ago

The 18th term of an arithmetic sequence is 49 and the first term is 15.

Tju [1.3M]

Answer:

Step-by-step explanation:

49-15=34

34/17=2

For this sequence, you can write this function:

f(x)=15+2(x-1)

Check:

f(18)=15+2(18-1)

f(18)=15+2(17)

f(18)=15+34

f(18)=49

So:

f(10)=15+2(10-1)

f(10)=15+2(9)

f(10)=15+18

f(10)=33

5 0

3 years ago

Three good friends are in the same algebra class. Their scores on a recent test are three consecutive even integers whose sum is

klio [65]

Let the lowest score be x.

The 3 consecutive even scores are:

1st score = x

2nd score = x + 2

3rd score = x + 4

Sum of their score is 270:

x + (x + 2) + (x + 4) = 270

Solve x:

x + (x + 2) + (x + 4) = 270

x + x + 2 + x + 4 = 270

3x + 6 = 270

3x = 264

x = 88

Find their scores:

1st score = x = 88

2nd score = x + 2 = 88 + 2 = 90

3rd score = x + 4 = 88 + 4 = 92

Answer: The scores are 88, 90 and 92

6 0

3 years ago

Identify the equivalent expression for each of the expressions below. Root(5, (m + 2) ^ 3). Root(3, (m + 2) ^ 5). Root(5, m ^ 3)

vesna_86 [32]

Answer:

1. $(\sqrt[5]{(m+2)})^{3} = (m+2)^{\frac{3}{5}}$

2. $(\sqrt[3]{(m+2)})^{5} = (m+2)^{\frac{5}{3}}$

3. $\sqrt[5]{(m)}^{3}+2 = m^{\frac{3}{5}}+2$

4. $\sqrt[3]{(m)}^{5}+2 = m^{\frac{5}{3}}+2$

Step-by-step explanation:

Recall that

$(\sqrt[n]{x})^{m} = (x^{\frac{m}{n}})$

Where $x^{m}$ is called radicand and n is called index

1. Root(5, (m + 2) ^ 3)

In this case,

n is 5

m is 3

x = (m + 2)

$(\sqrt[5]{(m+2)})^{3} = (m+2)^{\frac{3}{5}}$

2. Root(3, (m + 2) ^ 5)

In this case,

n is 3

m is 5

x = (m + 2)

$(\sqrt[3]{(m+2)})^{5} = (m+2)^{\frac{5}{3}}$

3. Root(5, m ^ 3) + 2

In this case,

n is 5

m is 3

x = m

$\sqrt[5]{(m)}^{3}+2 = m^{\frac{3}{5}}+2$

4. Root(3, m ^ 5) + 2

In this case,

n is 3

m is 5

x = m

$\sqrt[3]{(m)}^{5}+2 = m^{\frac{5}{3}}+2$

6 0

3 years ago

3. A box contains 7 Green balls, 5 Red balls, and 3 Blue balls. A ball is randomly selected and its color is noted. Then it is r

ziro4ka [17]

Answer:

a. 7/45

b. 1/15

Step-by-step explanation:

15 total balls

a. Selecting 1 Blue ball and 1 Green ball

3/15 * 7/15 = 21/225 = 7/45

b. Selecting 1 Red ball and 1 blue ball

5/15 * 3/15 = 15/225 = 1/15

6 0

3 years ago