Answer:
28 sixth graders will attend
Step-by-step explanation:
Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:

(1)
By Quadratic Formula:

,
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
First, let's declare a variable
x = # of students
Now, let's create an equation to model the problem.
x * 0.273 = 125
Divide both sides by 0.273
x = 457.8 = 458 students.
Note, I rounded to the nearest whole number.
3/5 = 60%
20 ÷ 5 = 4
3 x 4 = 12
Answer is A) 12/20