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2 years ago

Please help I need help with this question

Mathematics

1 answer:

denpristay [2]2 years ago

5 0

Answer:

2.5% and 2.5 · 10^-3, 0.25, 2/5, √5

Step-by-step explanation:

0.25, 2/5, 2.5 · 10^-3, 2.5%, √5

Now let's list them all in the same form, why not decimals.

0.25 = 0.25

2/5 = 4/10 = 40/100 = 0.4

2.5 · 10^-3 = 2.5 · 0.01 = 0.025

2.5% = 0.025

√5 ≅ 2.236

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Linda got 11/16 in her math test. Write her grade in percent.

steposvetlana [31]

Answer:

69%

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

There are 158 students registered for American History classes. There are twice as many students registered in second period as

Margarita [4]

There are 28 students in first period and 56 students in sceond period and 74 students in third period

<em><u>Solution:</u></em>

Let the number of students in first period be "x"

Let the number of students in second period be "y"

Let the number of students in third period be "z"

<em><u>There are 158 students registered for American History classes.</u></em>

Therefore,

x + y + z = 158 ---------- eqn 1

<em><u>There are twice as many students registered in second period as first period</u></em>

number of students in second period = twice of number of students in first period

y = 2x ------- eqn 2

<em><u>There are 10 less than three times as many students in third period as in first period</u></em>

number of students in third period = 3 times number of students in first period - 10

z = 3x - 10 ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

x + 2x + 3x - 10 = 158

6x = 168

<em><u>Substitute x = 28 in eqn 2</u></em>

y = 2(28)

<em><u>Substitute x = 28 in eqn 3</u></em>

z = 3(28) - 10

z = 84 - 10

Thus there are 28 students in first period and 56 students in sceond period and 74 students in third period

5 0

2 years ago

Simplify negative 5 minus the square root of negative 44 negative 5 minus 4 times the square root of 11 i negative 5 minus 4 i t

Anika [276]

Answer:

$-5-\sqrt{-44}=-5-2\sqrt{11}i$

Step-by-step explanation:

We want to simplify:

$-5-\sqrt{-44}$

We rewrite the expression under the radical sign to obtain:

$-5-\sqrt{4\times11\times -1}$

We split the expression under the radical sign to get:

$-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}$

Recall that:

$\sqrt{-1}=i$

This implies that:

$-5-\sqrt{4} \times \sqrt{11} \times \sqrt{-1}=-5-2\sqrt{11}i$

Therefore $-5-\sqrt{-44}=-5-2\sqrt{11}i$

6 0

3 years ago

Mr. Hayden's Bible class collected $11

ki77a [65]

This is the only way I can think of this mathematically. This took a good 20 minutes for me. You need to guess and check. Like try 17 quarters, 50 nickels, and 37 dimes etc. until you get 11.00. My numbers are mathematically correct but we both know you cant have 18.909 quarters so. lol

Answer:

Quarters: 18.909

Nickels: 49.818

Dimes: 37.818

Somewhere around those numbers.

Step-by-step explanation:

$11.00 total in coins

Nickel = $0.05

Dime = $0.10

Quarter = $0.25

(n*0.05) + (d*0.10) + (q*0.25)

Solve the equation for q.