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GuDViN [60]
2 years ago
15

What is the slope of a parallel line with the equation of y=1/2x+6?

Mathematics
2 answers:
Helga [31]2 years ago
6 0

Answer:

Using the slope-intercept form, the slope is −12 . All lines that are parallel to y=−x2−6 y = - x 2 - 6 have the same slope of −12 .

Step-by-step explanation:

Dmitry_Shevchenko [17]2 years ago
6 0

Answer:

1/2

Step-by-step explanation:

A parallel line has the same slope, so the slope will be equal to the slope of the equation y=1/2x+6

Boom.

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Which of these relations on the set {0, 1, 2, 3} are equivalence relations? If not, please give reasons why. (In other words, if
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Answer:

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(4)Not symmetric and Not Transitive, (2,1) is not in the set

Step-by-step explanation:

A set is said to be an equivalence relation if it satisfies the following conditions:

  • Reflexivity: If \forall x \in A, x \rightarrow x
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  • Transitivity: \forall x,y,z \in A, $if x \rightarrow y,$ and y \rightarrow z, $ then x \rightarrow z

(1) {(0,0), (1,1), (2,2), (3,3)}

(3) {(0,0), (1,1), (1,2), (2,1), (2,2), (3,3)}

The relations in 1 and 3 are Reflexive, Symmetric and Transitive. Therefore (1) and (3) are equivalence relation.

(2) {(0,0), (0,2), (2,0), (2,2), (2,3), (3,2), (3,3)}

In (2), (0,2) and (2,3) are in the set but (0,3) is not in the set.

Therefore, It is not transitive.

As a result, the set (2) is not an equivalence relation.

(4) {(0,0), (0,1), (0,2), (1,0), (1,1), (1,2), (2,0), (2,2), (3,3)}

(1,2) is in the set but (2,1) is not in the set, therefore it is not symmetric

Also, (2,0) and (0,1) is in the set, but (2,1) is not, rendering the condition for transitivity invalid.

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Step-by-step explanation:

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Step-by-step explanation:

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