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2 years ago

Which equation represents the function shown on the graph?

Mathematics

1 answer:

Anna11 [10]2 years ago

4 0

Answer:

x = 0, y = 0

Step-by-step explanation:

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Classify the shape as precisely as possible based on its markings.

AlekseyPX

Answer:

Step-by-step explanation:

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3 years ago

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Approximately what percentage of U.S. national income is paid to workers, as opposed to owners of capital and land? Select one:

Bezzdna [24]

Answer:

d. 50 percent

Step-by-step explanation:

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3 years ago

For the following exercises, solve each inequality and write the solution in interval notation.

Pie

Answer:

The solution of the given set in interval form is $(-\infty,-4] \cup[12, \infty)$ .

Step-by-step explanation:

It is given in the question an inequality as $|x-4| \geq 8$ .

It is required to determine the solution of the inequality.

To determine the solution of the inequality, solve the inequality $x-4 \geq 8$ and, $x-4 \leq-8$

Step 1 of 2

Solve the inequality $x-4 \geq 8$

$\begin{aligned}&x-4 \geq 8 \\&x-4+4 \geq 8+4 \\&x \geq 12\end{aligned}$

Solve the inequality $x-4 \leq-8$ .

$\begin{aligned}&x-4 \leq-8 \\&x-4+4 \leq-8+4 \\&x \leq-4\end{aligned}$

Step 2 of 2

The common solution from the above two solutions is x less than -4 and $x \geq 12$ .

The solution set in terms of interval is $(-\infty,-4] \cup[12, \infty)$ .

7 0

1 year ago

Jack,sally, and joe all work in a bookstore.jack sold 126 books.joe 1/2 as many books as jack,and sally sold 1/3 as many books a

Darina [25.2K]

Sally sold 2302323 books!

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3 years ago

What is the equation of the circle that has its center at -26,120 and passed through the origin

OlgaM077 [116]

well, first off let's check those two points, we know it's centerd at (-26 , 120) and we also know it passes through (0 , 0), so the distance between those two points is its radius

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{-26}~,~\stackrel{y_2}{120})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{radius}{r}=\sqrt{(~~-26 - 0~~)^2 + (~~120 - 0~~)^2} \implies r=\sqrt{(-26)^2 + (120 )^2} \\\\\\ r=\sqrt{( -26 )^2 + ( 120 )^2} \implies r=\sqrt{ 676 + 14400 } \implies r=\sqrt{ 15076 } \\\\[-0.35em] ~\dotfill$

$\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{-26}{h}~~,~~\underset{120}{k})}\qquad \stackrel{radius}{\underset{\sqrt{15076}}{r}} \\\\[-0.35em] ~\dotfill\\\\ ( ~~ x - (-26) ~~ )^2 ~~ + ~~ ( ~~ y-120 ~~ )^2~~ = ~~(\sqrt{15076})^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill (x+26)^2+(y-120)^2 = 15076~\hfill$

3 0

1 year ago