<h3>
Answer:</h3>
C. x^5 + 5x^4y + 10x^3y^2 + 10x^2y^3 + 5xy^4 + y^5
<h3>
Step-by-step explanation:</h3>
Wrong terms are bolded:
A. x5 + 5x4y + 10x3y2 + 10x3y3 + 5xy4 + y5
B. x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + y4
C. x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + y5
D. x5 + 5x4y4 + 10x3y3 + 10x2y2 + 5xy + y5
The sum of exponents should always be 5.
Answer:
the answer is an-as-1+1;a,=1
The wrong statement in Viktor's summary is When a round solid ball is placed in a box, the ball takes the shape of the box
The matter has three main states which are
These states define the way we interact and manipulate materials. For instance:
- Liquids take the shape of the container that contains them. For example water, milk, soda, among others.
- Solids have a defined shape and do not deform when manipulated or placed inside another container. For example, a round solid ball.
- Gases generally do not have colors and their atoms are not organized so they do not have a definite shape and take the shape of their container. For example, the air in a balloon.
According to the above, the error in Viktor's summary is in the first phase, and the correct statement is A. because solids does not take the shape of its container.
Learn more in:
Answer:
Step-by-step explanation:
10y-37 = 4y+7
by transposing,
10y-4y = 7+37
6y = 44
y = 44/6
hope this helps
plz mark it as brainliest!!!!!!
x = –6
Solution:
Given expression is
.
Step 1: Isolate the radical by subtracting 5 from both sides of the equation.
![\Rightarrow\sqrt[3]{x-2}+5-5=3-5](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%2B5-5%3D3-5)
![\Rightarrow\sqrt[3]{x-2}=-2](https://tex.z-dn.net/?f=%5CRightarrow%5Csqrt%5B3%5D%7Bx-2%7D%3D-2)
Step 2: Cube both sides of the equation to remove the cube root.
![\Rightarrow(\sqrt[3]{x-2})^3=(-2)^3](https://tex.z-dn.net/?f=%5CRightarrow%28%5Csqrt%5B3%5D%7Bx-2%7D%29%5E3%3D%28-2%29%5E3)
Cube and cube root get canceled in left side of the equation.

Step 3: To solve for x.
Add 2 on both sides of the equation.


Hence the solution is x = –6.