Solve the equation. <img src="https://tex.z-dn.net/?f=w%2F3%20%3D%20-9" id="TexFormula1" title="w/3 = -9" alt="w/3 = -9"

If 5 hours = 40 $

SCORPION-xisa [38]

Answer:

7 hours

Step-by-step explanation:

6 0

3 years ago

Ravi walks 3.5km every day. How far does he walk in 7 days?

kolbaska11 [484]

24.5 you take 3.5 and times it by 7 do get the distance.

4 0

3 years ago

Read 2 more answers

Write an exponential function to describe the given sequence of numbers.

andriy [413]

Answer:

a(n) = 9·6^(n-1)

Step-by-step explanation:

The general term a(n) of a geometric sequence with first term a(1) and common ratio r is given by ...

a(n) = a(1)·r^(n-1)

Your sequence has first term 9 and common ratio 54/9 = 6, so the function describing it is ...

a(n) = 9·6^(n-1)

5 0

3 years ago

David drives 168 miles a week he fill his tank 2 times a week each fill up is 12 gallons what is gas mileage on his car

Umnica [9.8K]

I think it would be 7 miles per gallon. Just do Miles/Gallons per week.

5 0

3 years ago

Read 2 more answers

If a/b < c/d with b > 0, d > 0, prove that a+c / b+d lies between the two fractions a/b and c/d .

Tems11 [23]

Divide through everything by b :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ab + \dfrac cb}{1 + \dfrac db}$

Since a/b < c/d, it follows that

$\dfrac{a+c}{b+d} < \dfrac{\dfrac cd+\dfrac cb}{1 + \dfrac db}$

Multiply through everything on the right side by b/d to get

$\dfrac{a+c}{b+d} < \dfrac{\dfrac{bc}{d^2}+\dfrac cd}{\dfrac bd+1} = \dfrac{\dfrac cd\left(\dfrac bd+1\right)}{\dfrac bd+1} = \dfrac cd$

and so (a + c)/(b + d) < c/d.

For the other side, you can do something similar and divide through everything by d :

$\dfrac{a+c}{b+d} = \dfrac{\dfrac ad + \dfrac cd}{\dfrac bd + 1}$

and a/b < c/d tells us that

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ad + \dfrac ab}{\dfrac bd + 1}$

Then

$\dfrac{a+c}{b+d} > \dfrac{\dfrac ab + \dfrac{ad}{b^2}}{1 + \dfrac db} = \dfrac{\dfrac ab\left(1+\dfrac db\right)}{1 + \dfrac db} = \dfrac ab$

and so (a + c)/(b + d) > a/b.

Then together we get the desired inequality.

5 0

3 years ago