Answer:416
Step-by-step explanation: Based on the given problem above, it requires a trigonometric solution. So here it goes:
The climb distance is:200 * Sec [ArcTan [10/200]] = 10√ 401 km
and the decent distance is:300 * Sec [ArcTan [10/300]] = 10√901 km
So add the given results above with 500 km and this will be the additional distance that plane moves through the air.
The answer would be in the unit meters.
((10√401 +10√901−500)∗1000)=416 meters
Hope this is the answer that you are looking for.
First things first.. What type of triangle
If u are taking about a normal triangle here is some:
∠60+∠60+∠60
∠30+∠90+∠60
∠11+∠82+∠87
log(x+3)(2x+3)+log( x+3)( x+5) =2
logx(2x+3)+3(2x+3 )+log x(x+5)+3(x+5)
The best way to answer this is to find counterarguments for each answer to eliminate them as a possibility. ab doesn't have to be an integer, 2.5*3=7.5 . That's also not an imaginary number so that's out. And that's also not an irrational number so that's out too. Only choice left is rational number.
