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White raven [17]
2 years ago
13

Write a linear inequality to represent the information given. The total fees for the high school play are $220. Tickets to the p

lay cost $5 for students and $7 for nonstudents. Write a linear inequality that describes the number of student and nonstudent tickets that need to be sold for the drama class to be able to pay the fees. Let x represent the number of student tickets and let y represent the number of nonstudent tickets.
Mathematics
1 answer:
Vladimir [108]2 years ago
5 0

Answer:

$5x + $7y ≥ $220

Step-by-step explanation:

Total Fees = $220

Total income is $5x plus $7y

Income = $5x + $7y

We want the total income to be equal to, or greater than, $220:

$5x + $7y ≥ $220

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Step-by-step explanation:

y =10 -3×​

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I need the answer but I am really looking to get a good understand of this.
omeli [17]

Answer:

y^{\frac{-5}{4}}

Step-by-step explanation:

To evaluate or simplify expressions with exponents, we use exponent rules.

1. An exponent is only a short cut for multiplication. It simplifies how we write the expression.

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3. When we divide terms with the same bases, we subtract exponents.

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3 0
3 years ago
The competitive advantage of small American factories such as Tolerance Contract Manufacturing lies in their ability to produce
statuscvo [17]

Answer:

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly higher than 0.0004, so there is no a violation of the specifications.

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

n=30 represent the sample size

\alpha=0.05 represent the confidence level

s^2 =0.0005 represent the sample variance obtained

\sigma^2_0 =0.0004 represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is violated, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 \leq 0.0004

Alternative hypothesis: \sigma^2 >0.0004

Calculate the statistic

For this test we can use the following statistic:

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

\chi^2 =\frac{30-1}{0.0004} 0.0005 =36.25

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 29. And since is a right tailed test the p value would be given by:

p_v =P(\chi^2 >36.25)=0.1664

In order to find the p value we can use the following code in excel:

"=1-CHISQ.DIST(36.25,29,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that p_v >\alpha so on this case we have enough evidence in order to FAIL reject the null hypothesis at the significance level provided. And that means that the population variance is not significantly higher than 0.0004, so there is no a violation of the specifications.

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Answer:

(x+[-1], y+[1])

Step-by-step explanation: Hope this helps

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