So we start with the $60 untouched.
Then we add the tax which is $60•0.07= 4.20 that is the tax
Then add the tax to the total $60 + $4.20= $64.20
Next we must add the tip so $60•0.15= 9.
Then $64.20 + $9.00 = $73.20
Total cost of meal $73.20
Any questions? :)
Answer:
2 cups
Step-by-step explanation:
Answer:
e
Step-by-step explanation:
The cube on the top, the one with the width of 4 is Cube 1.
The other one is Cube 2.
The length of the cube is 4, the width 2, and the height 5.
We know the length is 4 because we can look at the side, where both measurements 6 ft and 3 ft can be found.
We know that the height is 5 because for Cube 2, the height is 3. The total height is 8, so we subtract 3 from 8. We get our difference of 5.
V = l x w x h
V = (4)(2)(5)
V = (8)(5)
V = 40.
Cube 2 has a length is 6, the width 2, and the height 3.
V = l x w x h
V = (6)(2)(3)
V = (12)(3)
V = 36
We add the volumes of both cubes.
40 + 36 = 76
probs not right but hope it helped :)
Answer: A
Step-by-step explanation: B is a simile, D isn't true, and C doesn't exist (there is no type of figurative language that means that). I hope this helps you out!
Using the <u>normal distribution and the central limit theorem</u>, it is found that there is a 0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.
In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, for a proportion p in a sample of size n, the sampling distribution of sample proportions has mean and standard error
In this problem:
- Sample of 500 customers, hence .
- Amazon believes that the proportion is of 70%, hence
The <u>mean and the standard error</u> are given by:
The probability is the <u>p-value of Z when X = 0.68</u>, hence:
By the Central Limit Theorem
has a p-value of 0.1635.
0.1635 = 16.35% probability of a sample result with 68% or fewer returns prior to the third day.
A similar problem is given at brainly.com/question/25735688