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irina [24]
2 years ago
6

I still don't really have a single clue of this lol​

Mathematics
1 answer:
Shtirlitz [24]2 years ago
8 0

Answer: Supplementary

X = 17

Step-by-step explanation:

Have a good day

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The sum of the first four terms of an arithmetic sequence is $10$. If the fifth term is $5$, what is the sixth term?
Nookie1986 [14]

The sixth term of an arithmetic sequence is 6

<h3>How to find arithmetic sequence?</h3>

The sum of the first four terms of an arithmetic sequence is 10.

The fifth term is 5.

Therefore,

sum of term = n / 2(2a + (n - 1)d)

where

  • a = first term
  • d = common difference
  • n = number of terms

Therefore,

n = 4

10 = 4 / 2 (2a + 3d)

10 = 2(2a + 3d)

10 = 4a + 6d

4a + 6d = 10

a + 4d = 5

4a + 6d = 10

4a + 16d = 20

10d = 10

d = 1

a + 4(1) = 5

a = 1

Therefore,

6th term = a + 5d

6th term = 1 + 5(1)

6th term = 6

learn more on sequence here: brainly.com/question/24128922

#SPJ1

7 0
1 year ago
Sam divided a rectangle into 8 congruent
VMariaS [17]

Answer:

40cm²

Step-by-step explanation:

pretty sure bc there are 8 equal 5 cm² pieces meaning you multiply by 8 for the answer. 5•8=40. I think rofl

3 0
2 years ago
Yo what's 0.994 rounded to the nearest tenth
krek1111 [17]

Answer:To round 0.994 to the nearest tenth consider the hundredths’ value of 0.994, which is 9 and equal or more than 5. Therefore, the tenths value of 0.994 increases by 1 to 0.

0.994 rounded to the nearest tenth = 1.0

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A rectangle is transformed according to the rule r0, 90º. the image of the rectangle has vertices located at r'(–4, 4), s'(–4, 1
Korvikt [17]

Answer:

Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

Counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Step-by-step explanation:

Given  : rectangle has vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4)

To find :  transformed according to the rule 90º , what is the location of q?

Solution : we have given that

vertices located at r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4).

By the rule of 90º rotation clock wise rule : (x ,y ) →→ ( y , -x )

90º rotation counter clock wise rule : (x ,y ) →→ ( -y , x ).

Then   Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

Therefore, Clockwise vertices of q' ( -3 ,4) →→ q( 4 , 3 ).

counter clock wise rule : q' (-3 ,4 ) →→ q( -4 , -3 ).

4 0
3 years ago
Read 2 more answers
Read the true statement below and tell whether the converse, inverse, and contrapositive are also true.
IgorC [24]

Converse: False because he can live somewhere else but still belong in Hawaii

Inverse: False because he can live somewhere else but still belong in Hawaii

Contrapositive: True because Honolulu belongs to Hawaii so if he doesn't live in Hawaii he absolutely can't live in Honolulu

5 0
3 years ago
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